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Contact [7]
4 years ago
14

What is the reciprocal of -2/3

Mathematics
2 answers:
ryzh [129]4 years ago
8 0
3/-2

I Hoped I Helped

<span>ΩΩΩΩΩΩΩΩΩΩ</span>
Ksju [112]4 years ago
8 0
Its not 3/-2 because its still negative; when u flip a reciprocal it is either positive or negative! if its already negative then your reciprocal has to be positive so the answer to your question would be 3/2
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Will mark the brainliest <br> And thank you:)
Vinvika [58]

\sf{\implies Range = Highest \: - lowest }

→ Range of Lewistown = 74 - 64

→ Range of Lewistown = 10 .

→ Range of Hamersville = 71 - 55

→ Range of Hamersville = 16 .

☆ Range of Hamersville - Range of Lewistown

→ 16 - 10

→ 6

Answer → The range for Hamersville is 6 more than the range for Lewistown .

5 0
3 years ago
Find the slope, distance and midpoint between
Dovator [93]

Answer:

Slope- 4

Distance- 12.4

Midpoint- (6,8)

Step-by-step explanation:

Slope- \frac{y2-y1}{x2-x1}

\frac{2-14}{4-7} =\frac{-12}{-3}=4

Distance- d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

d = \sqrt{(4 - 7)^2 + (2-14)^2}

d = \sqrt{-3^2 + -12^2}d = \sqrt{144+9}=\sqrt{153}

\sqrt{153} = 12.4

Midpoint- \frac{x1+x2}{2} ,\frac{y1+y2}{2}

\frac{7+4}{2} =\frac{12}{2} = 6=x

\frac{14+2}{2} = \frac{16}{2} = 8 = y

(6,8)

6 0
3 years ago
What are equivalent expressions for 6(y-1) and 64x+80
snow_tiger [21]
To find equivalent expressions, distribute the first one and factor the second one.

6(y-1) \\  (6*y)+(6*-1) \\ 6y-6 \\  \\ 6(y-1)=6y-6 \\  \\ 64x+80 \\ 16( \frac{64}{16}x+ \frac{80}{16}) \\ 16(4x+5) \\ \\ 64x+80=16(4x+5)
4 0
3 years ago
Cot²3x - 3cot3x +2 = 0<br> cotx = t<br> what equation for t
kumpel [21]

Answer:

Step-by-step explanation:

cot²(3x)=y

y²-3y+2=0

y²-y-2y+2=0

y(y-1)-2(y-1)=0

(y-1)(y-2)=0

y=1,y=2

cot3x=1

tan 3x=1=tan (π/4)=tan (nπ+π/4)

3x=nπ+π/4=(4nπ+π)/4=(4n+1)π/4

x=(4nπ+1)π/12,n is an integer.

cot 3x=2

tan 3x=1/2

3x=tan^{-1}(1/2)≈26.57°+360n

x≈8.86°+120n

6 0
3 years ago
Can you help me with 10 and 12
lubasha [3.4K]
Here are the answers for 10 and 12

6 0
3 years ago
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