We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
Answer:
Brainliest
Step-by-step explanation:
2x+2 = 5x-10
3x=12
x=4
Answer:
Approximately 
percent
Step-by-step explanation:
To find a percentage, take the part, divide it by the whole, and multiply that quotient by 100. As an algebraic expression, that would be 
.
In this case, the part is 
and the whole is 
. Therefore, our answer is 
percent. Hope this helps!
Answer: 30
Step-by-step explanation: Make x 0 and set up the equation 0+y=30. Subtract 0 from both sides and then 30-0 equals 30 so y = 30
Answer:
I'm sorry I'm you can try to see if calculater soup can help you with this problem
