<span>The answer to the question is 0 percent. In order to have wrinkled seeds, the offspring must inherit two recessive alleles from the parents. From the cross of RRYY and RrYy, there is no way for the offspring to have wrinkled seeds as one of the parents doesn't have the recessive gene for it, the RRYY parent. Because of this there is 0 percent probability of having an offspring that has wrinkled seeds and yellow seed color.</span>
A word pharse that read the same backward as forward . it's about genetic table
Answer:
By looking at human embryo we can determine that it has a postanal tail.
Explanation:
Human embryo is a a process of life cycle that takes place after the fertilization. It takes 9 months for a human embryo to be fully developed. If we take a look at a human embryo, we will notice that it has a postanal tail.
Postanal tail is simply an extension of body. It is only during the embryonic stage that the postanal tail can be found. After the birth this feature cannot be found.
You are going to subract to get
36.4 - 21.0 = 15.4m
The distance of the object is 15.4 meters away from where it first began
<span>The answer is B. 72.25 percent.
The Hardy-Weinberg principle can be used:</span>
<em>p² + 2pq + q² = 1 </em>and <em>p + q = 1</em>
where <em>p</em> and <em>q</em> are the frequencies of the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq</em> are the frequencies of the genotypes.
<span>The <em>p</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15
To calculate the <em>P</em> allele frequency (<em>p</em>), the formula <em>p + q = 1</em> can be used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85
Knowing the frequency of the <em>P</em> allele (<em>p</em>), it is easy to determine the frequency of the <em>PP </em>genotype (<em>p²</em>):
p² = 0.85² = 0.7225
Expressed in percentage, p² = 72.25%.</span>
