Can someone help me please

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .

The equation for a sphere of radius $r$ and center $\left(x_0,\, y_0,\, z_0\right)$ would be:

$\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2$ .

In this case, the equation would be:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2$ .

Simplify to obtain:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56$ .

Expand the squares and simplify to obtain:

$x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ .

8 0

3 years ago

What is the percent of increase from 30 to 54?<br><br> Write your answer using a percent sign (%).

just olya [345]

54 - 30 = 24
Take the orginal number and place on the bottom
The orginal number is 30
24/30, if you need to simply find this number it will be 4/5
When you divide 4/5 it will be .80 or 80%
5 divide by 4 is equal to
Answer: 80%
Hope this help

7 0

3 years ago

Guys please which one is the right answer

kirza4 [7]

Answer: I think the answer is B

Step-by-step explanation:

8(x-4) = 8(1-4) = 8-32

2(4x-16) =2(4*1-16) = 8-32

8(x-4) = 8(2-4) = 16-32

2(4x-16) = 2(4*2-16) = 16-32

8 0

3 years ago

Read 2 more answers

What is the slop of 2x+3

seraphim [82]

Answer:

2

Step-by-step explanation:

The slope, or rate of change in any function is the number multiplied by the independent variable (in this case x).

3 0

3 years ago

Read 2 more answers

The width of a rectangle is 5 meters less than its length. The area is 84 square

VARVARA [1.3K]

Answer:

12 and 7 meters

Step-by-step explanation:

The area is 84 square meters and the width is 5 meters less than the length. 12 is the length and 7 is the width. 7 is 5 less than 12, and 12*7=84.

The length is 12 and the width is 7

7 0

3 years ago