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ollegr [7]
3 years ago
7

x-8/2=4 please help me asap this assignment is due in and hour! and please teach me how to do it! 10 points!!

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Answer:

ok so u do the opposite of 8/2 so do 8*2 which is 16 then add the answer which is 4 which equals 20 so 20- 8/2=4, 20-16=4

8090 [49]3 years ago
7 0

Answer:

x = 8

Step-by-step explanation:

x - 8/2 = 4

Follow your order of operations and divide first.

8/2 is 4

x- 4 = 4

Next, isolate the variable by using the additive property of equality.

x - 4 + 4 = 4 + 4

x = 8

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Which of the following would likely weigh about 8 pounds?
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Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
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Answer:  x = 9.6

=========================================================

Explanation:

We have two smaller right triangles that are glued together so to speak.

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Let's use the tangent rule to find the value of h

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h = 5*tan(55)

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Make sure your calculator is in degree mode. That value of h above is approximate.

--------------------------

Now focus on the smaller triangle on the right

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x = 7.14074003371058/cos(42)

x = 9.6088135029715

x = 9.6

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