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Advocard [28]
3 years ago
12

7B2%7D%20%7D%7B%20%5Cfrac%7B1%7D%7By%7D%20%7D%20" id="TexFormula1" title=" \frac{ {3x}^{2} }{xy} \times \frac{ {4xy}^{2} }{ \frac{1}{y} } " alt=" \frac{ {3x}^{2} }{xy} \times \frac{ {4xy}^{2} }{ \frac{1}{y} } " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
hjlf3 years ago
6 0
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{\frac{1}{y}}\implies \cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{y^{-1}}\implies \cfrac{3x^2x^1y^2}{xy^1y^{-1}}\implies \cfrac{3x^{2+1}y^2}{xy^{1-1}}
\\\\\\
\cfrac{3x^3y^2}{xy^0}\implies \cfrac{3x^3y^2}{x^1}\implies 3x^3y^2x^{-1}\implies 3x^{3-1}y^2\implies 3x^2y^2
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3 years ago
PLEASE HELP{ WILL GIVE BRAINLIEST
Volgvan

Answer:

\approx10.29\text{ feet}

Step-by-step explanation:

Please refer to the attachment.

By AA Similarity, the two triangles are similar.

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7 0
3 years ago
I need to algebraically prove that a polynomial I created is true for a project.
natta225 [31]

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<span>x^2-2xy+y^2</span>

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