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3 years ago

If c(x)=4x-2 and d(x)=x^2+5 , what is (c o d) (x)

Mathematics

1 answer:

Nookie1986 [14]3 years ago

3 0

Answer:

4x² + 18

Step-by-step explanation:

note that (c ○ d )(x) = c(d(x))

To evaluate substitute x = d(x) into c(x), that is

c(d(x))

= c(x² + 5)

= 4(x² + 5) - 2

= 4x² + 20 - 2

= 4x² + 18

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I 5 The sum 1 + 9 + 3 + 3 + i + 2 gives the amount of mix. 1+ 2+ 3+3+1+1

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Answer:

i = -7

Step-by-step explanation:

1) Set up equation

1+9+3+3+i+2 = 1+2+3+3+1+1

2) Combine like terms

18+i = 11

3) Factor out for the answer

18+i = 11

18-18+i = 11-18

i = -7

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Read 2 more answers

find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any tria

prohojiy [21]

Answer:

0.8746 = 87.46% probability of at least 6 failures in 7 trials.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

7 trials

This means that $n = 7$

The probability of success in any trial is 9%?

So the probability of a failure is 100 - 9 = 91%, which means that $p = 0.91$

Probability of at least 6 failures in 7 trials?

This is:

$P(X \geq 6) = P(X = 6) + P(X = 7)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{7,6}.(0.91)^{6}.(0.09)^{1} = 0.3578$

$P(X = 7) = C_{7,7}.(0.91)^{7}.(0.09)^{0} = 0.5168$

$P(X \geq 6) = P(X = 6) + P(X = 7) = 0.3578 + 0.5168 = 0.8746$

0.8746 = 87.46% probability of at least 6 failures in 7 trials.

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3 years ago