"y>-2x+2 and y>-2x+5" are illustrated graphically by 2 straight dashed lines with slope -2. The lines are parallel because their slopes (-2) are the same. One line has y intercept 2 and the other has y intercept 5. The latter is above the former. Since both inequality signs are " > " we must shade the area ABOVE each of the 2 lines. The solution set is the area of the graph that has been shaded twice, once for y>-2x+2 and again for y>-2x+5. It's y>-2x+5 that has been shaded twice; this area is immediately above the line y>-2x+5.
Answer:
y = 2x^2 is a parabola opening up with it's vertex at (0,0)... y=3x^2 -4 is also a parabola opening up, but it is 'thinner' in that it rises in y faster and it's vertex is at (0,-4)
Step-by-step explanation:
all equations of the type y = ax^2 + b are parabolas centered on the y-axis, soo the vertex is always on (0,b)
If a is positive then the parabola opens up,
the bigger a is, the 'thinner' the graph is, i.e. the faster the graph rises
the value of b determines the location of the vertex, if b is added, then the vertex rises over the x-axis, if b is subtracted then the vertex is below the x-axis
To find the inverse of the function, <span> f(x) = 1/4x-12, first interchange the variables of x and y
x=1/4y-12, now solve for y
1/4y=x+12, multiply by 4 on both sides
y=4x+48
Thus, the inverse of the function</span><span> f(x) = 1/4x-12 is 4x+48
Hope this helps!</span>
