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3 years ago

12

Pleas help with the ones you understand

1 answer:

max2010maxim [7]3 years ago

8 0

For 1- 4 all you have to do is multiply the numbers.

An easier way to write the same equation out would be to add multiplication signs. For example:

1. -2*3 is the same as (-2)(3)

When there are two parentheses next to each other without a sign in between, that means multiplication.

6-9 can also all be converted to be a whole number, which is what it want you to do.

11 and 12 is where you need to multiply and then add or subtract after you multiply.

Also, for 13 and 14, both the fractions can be converted to be a whole number, so you should turn them into whole numbers first and your life will be a lot easier.

And 15 is also the same thing as 11 and 12.

Extra Help: When you have two negative numbers, the answer will end being a positive and when there are two positive it will remain a positive, and a negative and positive number will be a negative.

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Help please ... thanks

lapo4ka [179]

Put the equation in desmos and you will get your answer :)

5 0

3 years ago

Read 2 more answers

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Lara planted some seeds. For every 3 seeds Lara planted, only 2 seeds grew.

Tresset [83]

Given:

For every 3 seeds Lara planted, only 2 seeds grew.

Altogether, 12 seeds grew.

To find:

The number of total seeds planted by Lara.

Solution:

It is given that for every 3 seeds Lara planted, only 2 seeds grew. It means the ratio of total seeds planted to seeds grew is 3:2.

Altogether, 12 seeds grew.

Let x be the number of total seeds planted by Lara. Then,

$x:12=3:2$

$\dfrac{x}{12}=\dfrac{3}{2}$

$x=\dfrac{3}{2}\times 12$

$x=18$

Therefore, the total number of seeds planter by Lara is 18.

3 0

3 years ago

A student received an 82% on an exam. If there were 50 questions on the exam, which ratio would show the number of questions ans

cluponka [151]

Easy

82% correct
82 out of 100 correct
82/100 of ttoal correct
total=50
82/100 times 50=
41/50 times 50=41 correct

ratio is 41:50

B is answer

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to r^9/r^3

Deffense [45]

$\cfrac{r^9}{r^3} =r^{9-3}=r^6$

4 0

3 years ago

Read 2 more answers