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Goshia [24]
3 years ago
10

Find the area of the shape (round to nearest tenth if necessary )

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

still

Step-by-step explanation:

still thinking sorry

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Help ur boy out abcdefghijklmnopqrstuvwxyz
Umnica [9.8K]

Answer:

  1. (-6, 10)
  2. (-10, 9)
  3. (-11, -6)
  4. (-5, 1)

Step-by-step explanation:

<em>(x,y) → (x-8, y+4)</em>

1. (2, 6)

(2-8, 6+4)

<u>(-</u><u>6, 10)</u>

2. (-2, 5)

(-2-8, 5+4)

<u>(-10, 9)</u>

3. (-3, -10)

(-3-8, -10+4)

<u>(-11, -6)</u>

ídk man u should connect it to <u>(11, -7)</u> since it's the only choice closest to the right answer, but If u can write the correct then write this. there's prolly an error in that quiz ídk

4. (3, -3)

(3-8, -3+4)

<u>(-5, 1)</u>

<u> </u>still not in the choices nanii but <u>(5, -14)</u> is the only choice left and also the closest, and even if u use calculator the correct answer is still (-5, 1). sigh, I hope this helper at least

5 0
3 years ago
Find the value of x so that f(x)=7
3241004551 [841]

Answer:

-3

Step-by-step explanation:

7 0
3 years ago
Can any one help with y = 2x + 4
geniusboy [140]

Answer:

It's in the screenshot hope it helpsss

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Please help me answer number 38.
julia-pushkina [17]

The request is to find the intersection of the two sets. By definition, the intersection of two sets is another set, composed by all the elements appearing in both sets.

In other words, P\cap Q is the set of all elements that P and Q have in common.

P contains all the numbers from 0 to 9, V contains all the odd numbers between 1 and 19. So, their intersection will be the odd numbers between 0 and 9, i.e.

P\cap Q=\{1, 3, 5, 7, 9\}

5 0
3 years ago
Suppose John opens a savings account with $1,000 that compounds interest daily. The APR at the time John deposits the account is
Fed [463]
\bf \qquad  \qquad  \textit{Annual Yield Formula}&#10;\\\\&#10;\left. \qquad \qquad  \right.\left(1+\frac{r}{n}\right)^{n}-1&#10;\\\\&#10;\begin{cases}&#10;r=rate\to 3.5\%\to \frac{3.5}{100}\to &0.035\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}&#10;\end{array}\to &365&#10;\end{cases}&#10;\\\\\\&#10;\left(1+\frac{0.035}{365}\right)^{365}-1
4 0
3 years ago
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