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3 years ago

A fair die is rolled 10 times what is the probability that an even number

Mathematics

1 answer:

bonufazy [111]3 years ago

8 0

Five out of ten or 1/2 depends if it is a 6-numbered die.

You might be interested in

-(x+6)-12=36 help me! Please

zmey [24]

Answer:

x=42

Step-by-step explanation:

-(42+6)-12=36

-(48)-12=36

48-12=36

hope this helps

4 0

3 years ago

the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width

dolphi86 [110]

Answer:

Length = 17 inches

Width = 12 inches

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Step-by-step explanation:

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As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

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Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

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Now, <u>According to the Question :</u>

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${\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}$

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${\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}$

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${\longrightarrow \qquad { {\sf{2 ( 2x + 5 )= 58 }}}}$

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${\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}$

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${\longrightarrow \qquad { {\sf{ 4x = 58 - 10}}}}$

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${\longrightarrow \qquad { {\sf{ 4x = 48}}}}$

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${\longrightarrow \qquad { {\sf{ x = \dfrac{48}{4} }}}}$

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${\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\: \: \bigstar$

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Therefore,

The width of the rectangle is 12 inches .

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Now, We are to find the length of the rectangle:

${\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}$

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${\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}$

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${\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}$

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Therefore,

The length of the rectangle is 17 inches .

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8 0

2 years ago

Read 2 more answers

Estimate. Round to the greatest place value. Circle whether the estimate is greater then or less then the actual product.

nataly862011 [7]

Answer:

The estimate is greater then.

Step-by-step explanation:

143*2=286

286*2=572 not 6,517

4 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

Which strategy would you use to divide 36÷6?Explain why you chose that strategy.

marusya05 [52]

I would use what times 6 = 36 because 6*6+36

7 0

3 years ago

Read 2 more answers