Question

In a fission reaction of U-235, there was a release of 9.20 × 1011 kJ of energy. What amount of mass in kilograms would have been lost?
Recall that c = 3 × 108 m/s.

Answer 1

 e = mc^2 
 
m = e / c^2 

Plug in your numbers in the appropriate units.
m=1.02 × 10^-5

Answer 2

Answer : The amount of mass in kilograms lost would be, $1.022\times 10^{-2}Kg$

Solution : Given,

Energy of released in the reaction = $9.20\times 10^{11}KJ$

Speed of light = c = $3\times 10^8m/s$

Formula used :

$E=m\times c^2$

where,

E = energy released

m = mass

c = speed of light

Now put all the given values in the above formula, we get the amount of mass would have been lost.

$9.20\times 10^{11}KJ=m\times (3\times 10^8m/s)^2$

$m=1.022\times 10^{-5}KJ/m^2s^{-2}=1.022\times 10^{-5}\times 10^3Kg=1.022\times 10^{-2}Kg$

conversion : $(1KJ/Kg=10^3m^2/s^2)$

Therefore, the amount of mass in kilograms lost would be, $1.022\times 10^{-2}Kg$