Which equation demonstrates that nuclear fusion forms elements that are heavier than helium?
2 answers:
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The empirical formula : C₁₂H₄F₇
The molecular formula : C₂₄H₈F₁₄
<h3>Further explanation</h3>mol C (MW=12 g/mol)
mol H(MW=1 g/mol) :
mol F(MW=19 g/mol)
mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7
Empirical formula : C₁₂H₄F₇
(Empirical formula)n=molecular formula
( C₁₂H₄F₇)n=562 g/mol
(12.12+4.1+7.19)n=562
(281)n=562⇒ n =2
Molecular formula : C₂₄H₈F₁₄
Answer:
The answer is
<h2>112.912 kPa</h2>Explanation:
The new pressure can be found by using the formula for Boyle's law which is
Since we are finding the new pressure
404.6 kPa = 404600 Pa
From the question we have
We have the final answer as
<h3>112.912 kPa</h3>Hope this helps you