<em><u>T</u></em><em><u>O</u></em><em><u> </u></em><em><u>F</u></em><em><u>I</u></em><em><u>N</u></em><em><u>D</u></em><em><u>:</u></em><em><u> </u></em> construct 3 equation starting with x=5?
<em><u>S</u></em><em><u>O</u></em><em><u>L</u></em><em><u>U</u></em><em><u>T</u></em><em><u>I</u></em><em><u>O</u></em><em><u>N</u></em><em><u>:</u></em><em><u> </u></em>
The equation is in the form of variable and constant equating.
Let the equation be x=5.
<em><u>T</u></em><em><u>O</u></em><em><u> </u></em><em><u>C</u></em><em><u>R</u></em><em><u>E</u></em><em><u>A</u></em><em><u>T</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>N</u></em><em><u> </u></em><em><u>E</u></em><em><u>Q</u></em><em><u>U</u></em><em><u>A</u></em><em><u>T</u></em><em><u>I</u></em><em><u>O</u></em><em><u>N</u></em><em><u>,</u></em>
<em><u>F</u></em><em><u>I</u></em><em><u>R</u></em><em><u>S</u></em><em><u>T</u></em><em><u> </u></em><em><u>W</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>D</u></em><em><u>D</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>B</u></em><em><u>O</u></em><em><u>T</u></em><em><u>H</u></em><em><u> </u></em><em><u>S</u></em><em><u>I</u></em><em><u>D</u></em><em><u>e</u></em><em><u>,</u></em>
x + 5=5+5
=x + 5=10
<em><u>S</u></em><em><u>E</u></em><em><u>C</u></em><em><u>O</u></em><em><u>N</u></em><em><u>D</u></em><em><u> </u></em><em><u>W</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>U</u></em><em><u>B</u></em><em><u>R</u></em><em><u>A</u></em><em><u>C</u></em><em><u>T</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>B</u></em><em><u>O</u></em><em><u>T</u></em><em><u>H</u></em><em><u> </u></em><em><u>S</u></em><em><u>I</u></em><em><u>D</u></em><em><u>E</u></em><em><u>,</u></em>
x — 5=5—5
=x—5=0
<em><u>T</u></em><em><u>H</u></em><em><u>I</u></em><em><u>R</u></em><em><u>D</u></em><em><u> </u></em><em><u>W</u></em><em><u>E</u></em><em><u> </u></em><em><u>M</u></em><em><u>U</u></em><em><u>L</u></em><em><u>T</u></em><em><u>I</u></em><em><u>P</u></em><em><u>L</u></em><em><u>Y</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>B</u></em><em><u>O</u></em><em><u>T</u></em><em><u>H</u></em><em><u> </u></em><em><u>S</u></em><em><u>I</u></em><em><u>D</u></em><em><u>E</u></em><em><u>,</u></em>
5x=5×5
=5x=25
well u got the answer!
Yes. Broiled Sirloin:240 + Baked Potato:145 + salad:33 + fruit cocktail:57= 475
Answer:
R = (-12, 22)
Step-by-step explanation:
Unfortunately it's not a straight line, so gonna need to put in some extra work. Basically think of it like breaking it into it's horizontal and vertical components then doubling them.
From Q to M you move 10 spaces to the left, so to go from M to R you will go another 10 to the left. Similarly, you start at -10 for the y value and go up 16 to 6, and you will need to go up another 16 to get to R.
So for x, 8 -10 = -2 then -2 - 10 = -12, so R's x value is -12
y we do the same thing. Gonna do it in one step though. -10 + 16 + 16 = 22
So R is (-12, 22)
Answer:
it's the last one.
Step-by-step explanation:
both of them have ÀF as part of their angle.
Answer:
4) 6 students
5) 7 fewer students
6) No, you can not tell from the frequency table how many students ran a mile in exactly 12 minutes.
Step-by-step explanation:
4) you’d look at the row from 8:00-8:59.
5) Add the first two rows together (6+2=8), then subtract that by the sum of the last two rows (9+6=15), which is 7
6) There’s no pattern in the frequency table, and the data points would be plotted differently since it’d be from a range of times, not one set time.
Hope this helped, sorry if I’m wrong on #6 ;)
