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Yanka [14]
2 years ago
6

Solve 16^z+2 *64^z-2

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
5 0

Answer:

Simplify -> 16^z + 2^1+6z - 2

Step-by-step explanation:

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wel
If I could get more context then that would help. Because an exponent being an odd number doesn’t do anything, so it could be either a negative or a positive
4 0
3 years ago
A line passes through the point (–6, –3) and has a slope of 2/3 . Which point is on the same line?
navik [9.2K]

Answer:

The point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

  • The point (-6, -3)
  • The slope m = 2/3

Using the point-slope form

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

  • m = 2/3
  • (x₁, y₁) = (-6, -3)

substituting the values m = 2/3 and the point (-6, -3)  in the point-slope form

y-y_1=m\left(x-x_1\right)

y-\left(-3\right)=\frac{2}{3}\left(x-\left(-6\right)\right)

y+3=\frac{2}{3}\left(x+6\right)

Subtract 3 from both sides

y+3-3=\frac{2}{3}\left(x+6\right)-3

y=\frac{2}{3}x+4-3

y=\frac{2}{3}x+1

comparing with the slope-intercept form y=mx+b

Here the slope = m = 2/3

Y-intercept b = 1

We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

Given the line

y=\frac{2}{3}x+1

at x = 0, y = 1

Thus, the point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

5 0
2 years ago
What is the domain and range of f(x)=2|x+2|-8
RideAnS [48]

Answer:

The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}

Step-by-step explanation:

- The domain of the function is the values of x which make the

  function defined

- The rang is the corresponding values of y with the domain

- The parent function of f(x) is g(x) = IxI

- The graph of this function represented by 2 lines starting from  

  the origin, one of them with positive slope and the other with negative

  slope and both of them over the x-axis

- The Domain of g(x) is {x : x ∈ R} where R is the set of real numbers

- That mean the domain of g(x) is all real numbers

- The range of g(x) is {y : y ≥ 0}

- That mean the range is all real numbers greater than or equal to zero

- f(x) is the image of g(x) after some transformations

- g(x) multiplied by 2 that mean vertical stretch.

- Then x add by 2 that mean horizontal translation to the left by 2 units

- Then subtract 8 from it means vertical translation down by 8 units

- The figure of f(x) is the same lines but stretched vertically away from

   x-axis and moved to the left 2 units and down 8 units

- That means the image of the origin is (-2 , -8)

- So the domain does not change it is the all real numbers

- The domain of f(x) is {x : x ∈ R}

- But the range changes is because the graph of the function starts

 from -8 not from 0

- Then the range of f(x) is {y : y ≥ -8}

* The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}

- <em>Look to the attached graph for more understand</em>

7 0
3 years ago
What is 2+2+9+0+8+1+2+3+4+5+6+7+8+9
pentagon [3]
2+2+9+0+8+1+2+3+4+5+6+7+8+9 is 66
6 0
2 years ago
Read 2 more answers
Identify the slope and y-intercept of the line with the given equation:
miv72 [106K]
1) (solve for Y 1st)
-4y=16
y=-4
slope=0        y-inter= -4

2)(solve for X 1st)
6x=12
x=2
slope=undefined     y-inter= none
3 0
3 years ago
Read 2 more answers
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