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k0ka [10]
3 years ago
8

Can someone help me please

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0
1. The triangle is Isosceles and acute A (since there are two equal sides and the angles are less than 90)
2. Right triangle E (since there is a right angle)
3. The triangle is obtuse scalene T (since there are no equal sides and one angle is greater than 90)
4. Right isosceles O
5. Acute equilateral N
6. Obtuse scalene T<span />
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Writing an equation of a probably given the vertex and focus
White raven [17]

The equation of the vertical parabola in vertex form is written as

y=\frac{1}{4p}(x-h)^2+k

Where (h, k) are the coordinates of the vertex and p is the focal distance.

The directrix of a parabola is a line which every point of the parabola is equally distant to this line and the focus of the parabola. The vertex is located between the focus and the directrix, therefore, the distance between the y-coordinate of the vertex and the directrix represents the focal distance.

p=1-6=-5

Using this value for p and (3, 1) as the vertex, we have our equation

y=-\frac{1}{20}(x-3)^2+1

6 0
11 months ago
What is 6 divide by 5
lara31 [8.8K]
Hey there!

6 divided by 5 = 1.2


Hope this helps!
Have a great day! (:
7 0
3 years ago
A city has 5 new houses for every 9 old houses. If there are 35 new houses in the city, how many old houses are there?
Nezavi [6.7K]

Answer:

C.) 63

Step-by-step explanation:

You know what you insisted on me answering, so I'll answer here.

35 ÷ 5 = 7

7 x 9 = 63

7 0
3 years ago
Read 2 more answers
A. Reflection <br> B. Rotation <br> C. Translation <br> D. No Transformation
Luda [366]

Answer:D I think might be wrong

Step-by-step explanation:

8 0
3 years ago
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Is knowing the coordinates of the vertex of a parabola enough to determine the domain and range?
puteri [66]

The <em>correct answers</em> are:


C) No: we would need to know if the vertex is a minimum or a maximum; and

C)( 0.25, 5.875).


Explanation:


The domain of any quadratic function is all real numbers.


The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.


If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.


There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.


The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).

5 0
3 years ago
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