Answer:
(5, 11) and (2, 2)
Step-by-step explanation:
y = (x-2)² + 2
y + 4 = 3x
(x-2)² + 2 + 4 = 3x
x² - 4x + 4 + 6 = 3x
x² - 7x + 10 = 0
(x - 5)(x - 2) = 0
x - 5 = 0, x = 5
x - 2 = 0, x = 2
y = (5-2)² + 2 = 11
(5, 11)
y = (2-2)² + 2 = 2
(2, 2)
Answer:
4-7y
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2
Step-by-step explanation:
^ thats a fraction but anyway i dont know what the choices were so I simplified it
Answer:
-55 divided by (-11)
Because you can have a negative minute after dividing
Answer:
y = -2·x^2 - 5·x - 18
y = -2·(x^2 + 10·x + 36)
y = -2·(x^2 + 10·x + 36)
y = -2·(x - (-5 - √11·i))·(x - (-5 + √11·i))
Maybe there is a typo in the original question, because there is no factorisation in the real numbers.
Because the question is " find the minimum value of y" the coefficient before x^2 must be a positive number. so it could be
y = 2·x^2 - 5·x - 18
Can you check this out?
