All categories

2 years ago

PLEASE SOMEONE DO THIS FOR ME: Determine the x - and y - intercepts of the following linear function: 4x + 8y =16

Mathematics

2 answers:

ra1l [238]2 years ago

8 0

4x+8y=16

4x/4+8y/8=16÷4/8

x+y=16×8/4

x+y=16×2

x+y=32

Kitty [74]2 years ago

3 0

Answer:

x = 2 and y = 1

Step-by-step explanation:

4*2 = 8

8 * 1 =8

8+8=16

4(2) + 8(1) = 16

could pls have brainliest!!

You might be interested in

Kaylee is selling candles to raise money for her lacrosse team. The large candles sell for $25 each and the

AVprozaik [17]

Answer:25(20)+10(10)=600

X Y

Step-by-step explanation: sell 20 (X) Large candles and sell 10 (Y) small candles

3 0

3 years ago

What is the answer to this? PLEASE HELP!

Leno4ka [110]

12 inches in 1 foot
12*12*12 cubic inches in 1 cubic foot = 1728 in^2

So 7125 in^3 = 7125/1728 = 4.123 ft^3 to nearest thousandth

5 0

2 years ago

Which integer is 30 closest to

vesna_86 [32]

Answer:

7,4,15,6

Step-by-step explanation:

7,4,15,6

4 0

2 years ago

Read 2 more answers

Raise g to the 7th power, multiply the result by 4, then subtract f from what you have

WINSTONCH [101]

Answer:

f - 4(g^7)

It's simple algebraic operations!

7 0

1 year ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago