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NARA [144]
3 years ago
11

Mr. Borkowski ordered 3 boxes of pens for the supply room. There are 12 pens in each box. If there are now a total of 96 pens in

the supply room, including the ones Mr.Borkowski added, how many boxes of pens were already in there before his order arrived?
Mathematics
1 answer:
Sloan [31]3 years ago
4 0

Answer:

11 boxes

Step-by-step explanation:

multiply 3 by 12 then add the product of that to 96 pens then divide the sum which is 132 by 12 and you should get 11.

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Whats is the answer to 5/8 -1/10
LuckyWell [14K]

Answer:

Hello, Your answer will be 45

Step-by-step explanation:

5+8=5*+%=45 <em>Hope This Helps!</em>

5 0
3 years ago
Fred orders pictures from a photographer. Each picture costs $5.50. A one-time shipping fee of $4.25 is added to the cost of the
Alexus [3.1K]

Answer:

Fred ordered 12 pictures

Step-by-step explanation:

70.25-4.25 (one time shipping fee) =66

then you take 66 and divide it by the cost of each picture

66/5.50= 12 pictures

3 0
3 years ago
Read 2 more answers
Need help please!!!!
Orlov [11]

Answer:

\frac{m + n}{m - n }  =   \frac{ - 8 + 4}{ - 8 - 4}

=-4/-12=1/3 is your answer

5 0
3 years ago
A rental car company charges $31 per day to rent a car and $0.13 for every mile
lord [1]

Answer:

The number of days is at most 5 days

= d ≤ 5 days

Step-by-step explanation:

A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:

She plans to drive 500 miles.

• She has at most $220 to spend.

At most means Less than or equal to $220

The inequality for expressing this = ≤

Hence, the inequality which can be used to determine d, the number of days Jocelyn can afford to rent while staying within her budget.

$31 × d + $0.13 × 500 miles ≤ $200

The inequality is given as:

31d + 65 ≤ 220

Solving further

31d ≤ 220 -65

31d ≤ 155

d ≤ 155/31

d ≤ 5

Therefore, the number of days is at most 5 days

8 0
3 years ago
Pls help ASAP!! Pleaseee now!!
kap26 [50]
4/5 x 7= 28/5= 5 3/5
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3 years ago
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