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Lady_Fox [76]
3 years ago
15

Cedric's basketball team scored fewer than 76 points in their last game. Which of the following inequalities represents the numb

er of points Cedric's basketball team scored in their last game?
Mathematics
1 answer:
Lelechka [254]3 years ago
8 0

Answer: n

Step-by-step explanation:

Although you did not provide the inequalities, the only inequality that can represent the number of points Cedric's basketball team scored in their last game is the one shown below:

Let's call the number of points Cedric's basketball team scored in their last game: n.

You know that Cedric's basketball team scored fewer than 76 points in their last game. "Fewer than" means "less than", which is represented with the symbol < .

Therefore, you can represent the number of points Cedric's basketball team scored in their last game with the following inequality:

n

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The automobile assembly plant you manage has a Cobb-Douglas production function given by p = 10x^0.2 y^0.8
Zepler [3.9K]

Answer:

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

This value of Δy is not constant for a constant increase in production.

Step-by-step explanation:

We know that the production function is p = 10x^{0.2} y^{0.8}, and in the current situation p=1200 and x=130.

With this information we can calculate the actual budget level:

p_0 = 10x^{0.2} y^{0.8}\\\\1200=10*130^{0.2} y^{0.8}\\\\1200=26.47*y^{0.8}\\\\y=(1200/26.47)^{1/0.8}=45.33^{1.25}=117.62

The next year, with an increase in demand of 100 more automobiles, the production will be p_1=1300.

If we calculate y for this new situation, we have:

y_1=(\frac{p_1}{10x^{0.2}} )^{1.25}=(\frac{1300}{26.47} )^{1.25}=49.10^{1.25}=130

The budget for the following year is 130.

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

\Delta y=y_1-y_0=130.00-117.62=12.38

This value of Δy is not constant for a constant increase in production.

3 0
3 years ago
(x^3-2x^2-5x+6)÷(x-1) solve using long division, must show work​
shepuryov [24]
The answer to the question

7 0
3 years ago
How do u Solve 2x2 + 2x2 + 2 - 2x2 =
Crank
<span>2x2 + 2x2 + 2 - 2x2 =  4 + 4 +2 -4
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7 0
3 years ago
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The cost function in a computer manufacturing plant is C(x) = 0.28x^2-0.7x+1, where C(x) is the cost per hour in millions of dol
Licemer1 [7]

9514 1404 393

Answer:

  $562,500 per hour

Step-by-step explanation:

The cost will be a minimum where C'(x) = 0.

 C'(x) = 0.56x -0.7 = 0

  x = 0.7/0.56 = 1.25

The cost at that production point is ...

  C(1.25) = (0.28×1.25 -0.7)1.25 +1 = -0.35×1.25 +1 = 0.5625

The minimum production cost is $562,500 per hour for production of 1250 items per hour.

_____

<em>Additional comment</em>

This is different than the minimum cost <em>per item</em>. This level of production gives a per-item cost of $450. The minimum cost per item is $358.30 at a production level of 1890 per hour.

5 0
2 years ago
PEASE HELP ASAP!!! The sum of two numbers is 58.
agasfer [191]

Answer:

y=15

x=43

(any variable can be used, I used x and y to make it easier to show)

Step-by-step explanation:

x+y=58

x-y=28

get x by its self

x=58-y

then subsitute into the other equation

(58-y)-y=28

58-2y=28

-2y=-30

y=15

sub. again

x+15=58

x=43

8 0
3 years ago
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