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3 years ago

How to find domain and range on functions

1 answer:

6 0

The domain is the set of all possible x-values which will make the function "work", and will output real y-values. When finding the domain, remember: The denominator (bottom) of a fraction cannot be zero. The number under a square root sign must be positive in this section

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A pair of shoes is on sale for 15% off. With this discount, customers will save

mezya [45]

$9 is the part, 15% is the percent, and $60 is the whole

$9 is %15 of the whole. This means $9 is the part, 15% is the percent, and the whole is the total cost of the shoes after the discount. The total cost of the shoes after the discount is 60.

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3 years ago

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nordsb [41]

I don’t know i’m sorry

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3 years ago

Help! Can you please help

lakkis [162]

Answer:

14)= 2/3/23 × 1/9/14

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3 years ago

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PLEASEE SOMEONE ANSWER ILL DO ANYTHING ANYTHING PLEAASEEE HELP ME this is myh 6th time posting this ;[

Sonbull [250]

What is the problem?

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3 years ago

Select the equivalent expression.

Free_Kalibri [48]

Answer:

$\frac{7^{15}}{3^{30}}$

Step-by-step explanation:

The given expression is:

$(\frac{3^{-6}}{7^{-3}})^{5}$

Moving the expression to the other side in the fraction changes its sign to opposite. A numerator with negative exponent, when written in denominator will have the positive exponent. Using this rule, we can write:

$(\frac{3^{-6}}{7^{-3}})^{5}\\\\ = (\frac{7^{3}}{3^{6}} )^{5}$

The exponent 5 can be distributed to both numerator and denominator as shown:

$(\frac{7^{3}}{3^{6}} )^{5}\\\\ = \frac{(7^{3})^{5}}{(3^{6})^{5}}$

The power of a power can be written as a product. i.e.

$\frac{(7^{3})^{5}}{(3^{6})^{5}}\\\\ =\frac{7^{15}}{3^{30}}$

So, the expression similar to the given expression and with positive exponents is: $\frac{7^{15}}{3^{30}}$

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3 years ago

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