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3 years ago

How do use a net to find the surface area of a square Pyramid

Mathematics

1 answer:

Gekata [30.6K]3 years ago

7 0

Find the area of each shape first like first the middle square then the triangles and multiply the triangles by 4

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Write the equation that passes through the following points:<br><br> (5,0) and (−10,−5)

Vikentia [17]

Answer:

The answer is:

$y = \frac{1}{3} x - \frac{5}{3}$

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

$y = mx + b$

❃Incase you also forgot, The is what the slope formula is ☟

$m = \frac{y_2 - y_1 }{x_2 - x_1}$

➊ First: We are going to be solving for the slope.

$m = \frac{ - 5 - 0}{ - 10 - 5} = \frac{ - 5}{ - 15} = \frac{1}{3}$

➋Second: We find the y-intercept.

$y = mx + b \\ 0 = \frac{1}{3} (5) + b \\ 0 = \frac{5}{3} + b \\ \frac{ - \frac{5}{3} = - \frac{5}{3 } \: \: \: \: \: \: \: \: \: \: \: \: }{ - \frac{5}{3} = b}$

➌Third: Plug in.

$y = \frac{1}{3} x - \frac{5}{3}$

4 0

3 years ago

when graphing a line, if you use run over rise instead of rise over run, does that change the slope of the line? please help!!

steposvetlana [31]

yes , because run over rise wont give you a valid answer

4 0

3 years ago

3+×/2=10 <br> Is ×/2=7<br> And does ×=14

adoni [48]

$3+\dfrac{x}{2}=10\qquad|\text{subtract 3 from both sides}\\\\\dfrac{x}{2}=7\qquad|\text{multiply both sides by 2}\\\\\boxed{x=14}$

7 0

3 years ago

What is the perfect score between 144 and 169

madam [21]

Answer:

154

Step-by-step explanation:

if you write down all the numbers in a line then you go from 169 and 144 equally to the middle you would reach 154

5 0

3 years ago

Read 2 more answers

If the endpoints of ST are S (1,4) and T (5,2) then the midpoint is in Quadrant IV?

irina [24]

It is false that the midpoint is in quadrant IV

<h3>How to determine the midpoint location?</h3>

The endpoints are given as:

S (1,4) and T (5,2

The midpoint is

(x, y) = 0.5 *(x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 *(1 + 5, 4 + 2)

Evaluate the expression

(x, y) = (3, 3)

The point (3, 3) is located in the first quadrant

Hence, it is false that the midpoint is in quadrant IV