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DiKsa [7]
3 years ago
7

How do use a net to find the surface area of a square Pyramid

Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0
Find the area of each shape first like first the middle square then the triangles and multiply the triangles by 4 
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Solve equation by using the quadratic formula.<br> 2x2 + 13x = 0
Nadusha1986 [10]
THE answer is 17 because 2X2= 4+13= 17
Your Welcome :D
5 0
3 years ago
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How do you say 309099990 in word form
babunello [35]
<span>First of all, we need to put commas in the number so it would look less confusing 309 , 099 , 990 Hundred million hundred of thousnd Hundred So the correct way to say it would be : three hundred nine million ninety nine thousand nine hundred and ninetyHope this helps. Let me know if you need additional help!</span>
6 0
2 years ago
Decide whether each relation defines y as a function of x. Give the domain and range.
lisov135 [29]
Y=x².

This is te function of a parabola open upward

the domain is all values of x ={x/x∈z}
7 0
3 years ago
what is the coeffcient of a term that consists of a single variable?For example,what is the coefficient of x
Viktor [21]
1 easy
x=1x

if you have a cow, how many do you have? 1

if ou have an x, how many do you have? 1

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6 0
3 years ago
A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on
Alla [95]

Given:

The scale of a map is \dfrac{3}{4}\ in=80\ miles.

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

\dfrac{3}{4}\ in=80\ miles

It means, 80 miles in real life = \dfrac{3}{4}\ in on the map.

1 mile in real life = \dfrac{3}{4\times 80}\ in on the map.

60 mile in real life = \dfrac{3\times 60}{4\times 80}\ in on the map.

                              = \dfrac{180}{320}\ in on the map.

                              = \dfrac{9}{16}\ in on the map.

Therefore, the buildings are \dfrac{9}{16}\ in apart on the map.

7 0
3 years ago
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