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Hunter-Best [27]
3 years ago
9

At 8am,Ming Wei started travelling from Town A to Town B.At 8:40am, Ali started travelling from Town B to Town A.Mingwei's speed

and Ali's speed were 45km/h and 35km/h respectively.They did not change their speeds throughout the journey.When they met each other,their distance from Town A was twice their distance from Town B.Find the distance between Town A and Town B.

Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0
Let's write some equations.

Mingwei's distance from Town A after x hours from 8:00 is 45x.

Ali's distance from Town B after x hours is 30x-20, since he doesn't start walking for 40 minutes.

When Mingwei's distance is twice Ali's, they've met up (since their distance from Town A is twice their distance from Town B).

So, this gives 45x=60x-40, so 15x=40, so x=\frac{40}{15} = \frac{8}{3}, so the time is 10:40.

After \frac83 hours, Mingwei has traveled 45 * 8 / 3 = 120 kilometers while Ali has traveled sixty, so the distance between the towns is 180 kilometers.
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