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Hunter-Best [27]
3 years ago
9

At 8am,Ming Wei started travelling from Town A to Town B.At 8:40am, Ali started travelling from Town B to Town A.Mingwei's speed

and Ali's speed were 45km/h and 35km/h respectively.They did not change their speeds throughout the journey.When they met each other,their distance from Town A was twice their distance from Town B.Find the distance between Town A and Town B.

Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0
Let's write some equations.

Mingwei's distance from Town A after x hours from 8:00 is 45x.

Ali's distance from Town B after x hours is 30x-20, since he doesn't start walking for 40 minutes.

When Mingwei's distance is twice Ali's, they've met up (since their distance from Town A is twice their distance from Town B).

So, this gives 45x=60x-40, so 15x=40, so x=\frac{40}{15} = \frac{8}{3}, so the time is 10:40.

After \frac83 hours, Mingwei has traveled 45 * 8 / 3 = 120 kilometers while Ali has traveled sixty, so the distance between the towns is 180 kilometers.
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Consider these four data sets. Set A: {32, 12, 24, 46, 18, 22, 14} Set B: {4, 12, 11, 14, 11, 5, 12, 13, 18, 14} Set C: {5, 4, 9
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SET A

The elements of this set are,

32,12,24,46,18,22,24


We arrange this data set in ascending order to get,

12,18,22,24,24,32,46



The median for this data set is

median = 24


The mean for this data set can be calculated using the formula,

\bar X =  \frac{ \sum x}{n}

This implies that,

\bar X =  \frac{ 12 + 18 + 22 + 24 + 24 + 32 + 46}{7}

\bar X =  \frac{154}{7}  = 22
This data set is negatively skewed because the mean is less than the median.



SET B

This set contains the elements,

4, 12, 11, 14, 11, 5, 12, 13, 18, 14



We arrange the elements of this set in ascending order to obtain,

4,5,11,11,12,12,13,14,14,18

The median for this data set is,

median =  \frac{12 + 12}{2}  = 12

The mean is

\bar X =  \frac{4 + 5 + 11 + 11 + 12 + 12 + 13 + 14 + 14 + 18}{10}

.
\bar X  =  \frac{114}{10}  = 11.4

This data set is negatively skewed because the mean I'd less than the median.

SET C

The set C has elements,
5, 4, 9, 12, 14, 26, 22, 18

We arrange this set in ascending order to get,

4,5,9,12,14,18,22,26

The median of this data set is

median =  \frac{12 + 14}{2}  = 13


The mean of this data set is
\bar X =  \frac{4 + 5 + 9 + 12 + 14 + 18 + 22 + 26}{8}


\bar X =  \frac{110}{8}  = 13.75


This is a positively skewed distribution because the mean is greater than the median


SET D


The elements of this set are

1, 1, 1, 2, 2, 3, 3, 4, 5, 6

The median of this data set is

median =  \frac{2 + 3}{2}  = 2.5


The mean is
\bar X= \frac{1 + 1 + 1 + 2 + 2 + 3 + 3 +  4+ 5 + 6}{10}


\bar X= \frac{28}{10}  = 2.8

This data set is positively skewed because the mean is greater than the median.

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