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mario62 [17]
2 years ago
12

What are html documents also called?

Computers and Technology
1 answer:
11Alexandr11 [23.1K]2 years ago
4 0
HyperText Markup Language
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Write an if-else statement for the following: If user_tickets is less than 5, assign 1 to num_tickets. Else, assign user_tickets
Genrish500 [490]

Solution :

function tickets(user_tickets){

var num_tickets;

if (user_tickets < 5) {

num_tickets = 1;

return ('num_tickets: '+ num_tickets);

}

else {

num_tickets = user_tickets;

 return('num_tickets: '+ num_tickets);

}

}

// Testing the tickets function

// With user_tickets = 3, 5, 8, and 1

console.log(tickets(3));

console.log(tickets(5));

console.log(tickets(8));

console.log(tickets(1));

7 0
3 years ago
By default the normal style inserts a vertical space equal to _____ lines between each line of text
nika2105 [10]
By default the normal style inserts a vertical space equal to 1.5 size vertical   lines between each line of text.
3 0
2 years ago
How can I make a video game?
Rainbow [258]
You first need to figure out what kind of game you would like to create. Find codes and certain websites that will help you set up and or make a game.
3 0
2 years ago
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Write a java program called allDigitsOdd that returns whether every digit of a positive integer is odd. Return true if the numbe
Vlada [557]

Answer:

public class Digits

{

   public static boolean allDigitsOdd(int num)

   {

       boolean flag=true;

       int rem;

       while(num>0)

       {

           rem=num%10;

           num=num/10;

           if(rem%2==0)    // if a even digit found immediately breaks out of loop

           {

               flag=false;

               break;

           }

       }

       return flag;     //returns result

   }

   public static void main(String args[])

   {

       System.out.println(allDigitsOdd(1375));    //returns true as all are odd digits

   }

}

OUTPUT :

true

Explanation:

Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.

4 0
3 years ago
If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support
Molodets [167]

Answer:

Here is the JAVA program. I  have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

   Scanner input = new Scanner(System.in); // create object of Scanner

       String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

           String LOL = "laughing out loud";

           String IDK = "i don't know";

           String BFF = "best friends forever";

           String IMHO = "in my humble opinion";

           String TMI = "too much information";

           String TYT = "take your time";

           String IDC = "I don't care";

           String FYI = "for your information";

           String BTW = "by the way";

           String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

           System.out.println("Input an abbreviation:" + " ");

           if(input.hasNext()) { // reads the abbreviation form the user

           abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

    switch(abbreviation) {

       case "LOL" : System.out.println(LOL);

                    break;

       case "IDK" : System.out.println(IDK);

                    break;

       case "BFF" : System.out.println(BFF);

                    break;

       case "IMHO": System.out.println(IMHO);

                     break;

       case "TMI": System.out.println(TMI);

                     break;

       case "TYT": System.out.println(TYT);

                     break;

       case "IDC": System.out.println(IDC);

                     break;

       case "FYI": System.out.println(FYI);

                     break;

       case "BTW": System.out.println(BTW);

                     break;

       case "OMG": System.out.println(OMG);

                     break;

                     

       default    : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

5 0
3 years ago
Read 2 more answers
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