Answer:
The code to the given question can be given as:
Code:
1)
2 arrays that used to store 10 employee identification number and grosspay amount in parallel and its data-type is int and double.
int Employee_id[10]; //array that store integer value
double Weekly_Gross_Pay[10]; //array that store double value
2)
Define loop for print the details of employees’ identification number and weekly gross pay.
for(int i=0; i<10; i++)
{
cout <<Employee_id[i] <<" " << Weekly_Gross_Pay[i] << endl;
}
Explanation:
The explanation of the above code can be given as:
In Code (1) we declare two array that's data-type is integer and double. In Employee_id array it store the integer values and Weekly_Gross_Pay it store the double value.
In Code(2) It is used to print the value of array. In that code, we used for a loop because of its entry control loop and we know the size of the array. In this loop, we declare a variable (i) and initialized the value 0 and check the condition(i)less than 1 and increment of i. It prints all the 10 values.
Answer:
evaluation of decision effectiveness
Explanation:
Based on the information provided within the question it can be said that in this scenario she is in the stage of evaluation of decision effectiveness. This is the stage after the decision has been made in which the individual begins to analyze the decision and determine whether the decision was as effective as originally anticipated , and whether or not it was the correct decision.
Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
Resources :) You’re welcome
Explanation:
Age = 23.
To convert a base 10 number to hexadecimal number we have to repeatedly divide the decimal number by 16 until it becomes zero and store the remainder in the reverse direction of obtaining them.
23/16=1 remainder = 5
1/16=0 remainder = 1
Now writing the remainders in reverse direction that is 15.
My age in hexadecimal number is (15)₁₆.
