Answer:
Explanation:
The following code is written in Python. It is a recursive function that tests the first and last character of the word and keeps checking to see if each change would create the palindrome. Finally, printing out the minimum number needed to create the palindrome.
import sys
def numOfSwitches(word, start, end):
if (start > end):
return sys.maxsize
if (start == end):
return 0
if (start == end - 1):
if (word[start] == word[end]):
return 0
else:
return 1
if (word[start] == word[end]):
return numOfSwitches(word, start + 1, end - 1)
else:
return (min(numOfSwitches(word, start, end - 1),
numOfSwitches(word, start + 1, end)) + 1)
word = input("Enter a Word: ")
start = 0
end = len(word)-1
print("Number of switches required for palindrome: " + str(numOfSwitches(word, start, end)))
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Answer is salvation
1.
name = input("Enter your name: ")
num1 = int(input("Hello "+name+ ", enter an integer: "))
num2 = int(input(name+", enter another integer: "))
try:
if num1 % num2 == 0:
print("The first number is divisible by the second number")
else:
print("The first number is not divisible by the second number")
except ZeroDivisionError:
print("The first number is not divisible by the second number")
try:
if num2 % num1 == 0:
print("The second number is divisible by the first number")
else:
print("The second number is not divisible by the first number")
except ZeroDivisionError:
print("The second number is not divisible by the first number")
2.
import random, math
num1 = float(input("Enter a small decimal number: "))
num2 = float(input("Enter a large decimal number: "))
r = round(random.uniform(num1, num2), 2)
print("The volume of a sphere with radius " + str(r) + " is " + str(round(((4 / 3) * math.pi * (r ** 3)), 2)))
I hope this helps!
Answer:
D
Explanation:
I think putting hyperlink in essential pages is a good idea as it may guide a user
