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3 years ago

What is the ratio of the perimeter of the smaller triangle to the perimeter of the larger triangle?

Mathematics

1 answer:

Andrews [41]3 years ago

5 0

Answer:

Option C. $\frac{5}{6}$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

and

The scale factor is equal to the ratio of its corresponding sides

Let

z-----> the scale factor

$z=\frac{15}{18}$

simplify

$z=\frac{5}{6}$

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Dylan invested $20,000 in an account paying an interest rate of 5.3% compounded continuously. Assuming no deposits or withdrawal

almond37 [142]

Answer:

$24,240

Step-by-step explanation:

20,000 + 1,060 (5-1)

7 0

3 years ago

What is the range for f(x) = 2^x

Natali [406]

Given the function:

$f(x)=2^x$

The function can also be written as:

$y=2^x$

The range of the function will be all set of y values.

To find the range, let's graph the function below.

We have:

From the graph above, all possibe y values range from 0 to infinity.

Therefore, the range of the function is from zero infinity.

In interval notation:

Range = (0, +∞)

ANSWER:

4. (0, +∞)

6 0

1 year ago

Simplify 2b –7+3+4 –+3

Y_Kistochka [10]

Answer:

Hope this helps :-)

Step-by-step explanation:

<h3>I don't know which one it is, but the answer to the one in the picture is </h3><h2>4b+14</h2><h3>and the answer to the one on brainly is </h3><h2>2b-3</h2>

4 0

2 years ago

Read 2 more answers

The temperature was 6 degrees at midday.

Georgia [21]

Answer:

2 & 3

Step-by-step explanation:

they both equal -7

the temp dropped 7 degrees

8 0

2 years ago

Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum

lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

$\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\$

$\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\ (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\$

$=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3} \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\$

4 0

2 years ago