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Alexxandr [17]
3 years ago
7

What is -w(2w+7) distributive property

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0

Answer: -w(2w+7): -2w ^2 - 7w

Step-by-step explanation:

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C<br> What is the missing hypotenuse length? *<br> х<br> 6<br> 8
4vir4ik [10]

Step-by-step explanation:

By Pythagoras' Theorem, 6^2 + 8^2 = x^2.

x^2 = 36 + 64 = 100, x = 10.

7 0
3 years ago
С<br> 5<br> ө<br> А:<br> 15<br> B<br> Nearest tenth
lubasha [3.4K]

Step-by-step explanation:

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5 0
3 years ago
Pleasee help mee<br><br>12sin(x)-5cos(x)=6,5​
abruzzese [7]

We turn -5,12 into polar coordinates.  It's a Pythagorean Triple so

r = 13   Ф=arctan(-12/5) + 180°   ( in the second quadrant )

so -5 = 13 cos Ф, 12 = 13 sin Ф

12 sin x - 5 cos x = 6.5

13 sinФ sin x + 13 cos Ф cos x = 6.5  

13 cos(x - Ф) = 6.5

cos(x - Ф) = 1/2

cos(x - Ф) = cos 60°

x - Ф = ± 60° + 360° k     integer k

x = Ф ± 60° + 360° k  

x = 180° + arctan(-12/5) ± 60° + 360° k  

That's the exact answer;

x ≈  180° - 67.38° ± 60° + 360° k  

x ≈  122.62° ± 60° + 360° k  

x ≈  { 62.62°, 182.62°} + 360° k,  integer k

3 0
3 years ago
6(1) = 16<br> 6(n) = b(n − 1) + 1<br> Find the 2-term in the sequence.
Tresset [83]

Answer:

17

Step-by-step explanation:

Given

b(1)=16\\ \\b(n)=b(n-1)+1

Finding the second term of the sequence means to find b(2). To find b(2) substitute n=2 into the second expression:

b(2)=b(2-1)+1\\ \\b(2)=b(1)+1\\ \\b(2)=16+1\\ \\b(2)=17

6 0
3 years ago
In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o
ycow [4]

Answer:

A

Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,

  • \angle CBD\cong \angle ACD\cong \angle CBA
  • \angle DCB\cong \angle DAC\cong \angle BAC

So,

\triangle ABC\sim \triangle CBD\sim \triangle ACD

1. From the similarity \triangle ABC\sim \triangle CBD, you have

\dfrac{AB}{BC}=\dfrac{BC}{BD}\\ \\\dfrac{c}{a}=\dfrac{a}{s}

2. From the similarity \triangle ABC\sim \triangle ACD, you have

\dfrac{AB}{AC}=\dfrac{AC}{AD}\\ \\\dfrac{c}{b}=\dfrac{b}{r}

Hence, option A is true

5 0
3 years ago
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