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kolbaska11 [484]
2 years ago
5

two cars traveled equal distances in different amounts of time. car a traveled the distance in 2.4 hours and car b traveled the

distance in 4 hours. car a traveled 22 mph faster than car b. how fast did car A travel?
Mathematics
1 answer:
eduard2 years ago
6 0

Car A traveled a distance of 55 Mph

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IMPORTANT PLZ HELP!!!!
kolbaska11 [484]

Answer:

D

Step-by-step explanation:

|C|<|D|

So C≠D

6 0
2 years ago
Elect two ratios that are equivalent to 6 : 10
Vika [28.1K]
Answer is :
12:20
18:30
7 0
2 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
it costs $20 for 4 play tickets and $35 for 7 play tickets. Is cost per ticket constant? why or why not?
KonstantinChe [14]

Answer:

The cost per ticket is<u> constant</u>.

Step-by-step explanation:

Given:

It costs $20 for 4 play tickets and $35 for 7 play tickets.

Now, to get whether cost per ticket is constant or not.

So, if the cost per ticket is constant that means the cost of ticket for a play or more is fixed, non-varying and it does not change.

Now, we check it:

4 play tickets costs  = $20.

1 play tickets costs  = $20 ÷ 4 = $5.

So, 7 play tickets costs = $5 × 7 = $35.

Thus, the cost of ticket for play is not changing and it is constant.

So the cost per ticket is constant.

Therefore, the cost per ticket is constant.

4 0
3 years ago
Which sequence below represents an exponential sequence A.) {2,6,10,14,18,...} B.) {3,5,9,16,24,...} C.) {4,8,24,96,...} D.) {25
denis-greek [22]

Answer:

  D.)  {256,64,16,4,...}

Step-by-step explanation:

Look for the sequence in which adjacent terms are related by a common ratio.

  A. 10/6 ≠ 6/2

  B. 9/5 ≠ 5/3

  C. 8/4 ≠ 24/8

  D. 64/256 = 16/64 = 4/16 = 1/4 . . . . this exponential sequence has a common ratio of 1/4

6 0
2 years ago
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