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Veronika [31]
3 years ago
8

Anyone who is extremely smart in Math please help me with my online homework and I'm struggling with this assignments.

Mathematics
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

What kind of math

Step-by-step explanation:

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40,000 ft.2 to hectares (1 hectare = 10,000 m2)
frozen [14]

Answer:

1.2192 hectares

Step-by-step explanation:

1 foot² = .3048 meter²

40000 feet² * .3048 = 12192 meters²

12192/10000 = 1.2192

4 0
2 years ago
Read 2 more answers
The function y=5x+10 represents the total cost y of a group of x members to go paintballing.
never [62]

Answer:

The independent variable (x) represents the members to go paintballing.

The dependent variable (y) represents the total cost.

Step-by-step explanation:

The y is always dependent on the x. The number of people attending affects the total cost of the trip. The more people attend, the more it costs.

3 0
2 years ago
7 in.
fgiga [73]
258 cubic inches

Since the boxes are kind of on their own—>
First box: 7*2*12 = 168
Second box: 5*2*9=90
168+90 = 258
6 0
3 years ago
Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
3 years ago
Find the value of X so that the function has the given value t(x)=3x; t (x)= 24
Fed [463]

Answer:

here is your answer....

Step-by-step explanation:

lets take x as 8

t(8)=3*8

t(8)=24

Therefore:

we get t(x)=24 from equation t(x)=3x

8 0
2 years ago
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