A and C are correct, you have to multiply 32 by 4 and by 12, then add the aswers together to find how many juice boxes total.
For this case we have the following expression:

We clear the value of the variable "g", for this:
We multiply by 4 on both sides of the equation:

We divide by 3 on both sides of the equation:

We simplify:

Answer:

Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).
Answer:
B) y = x - 50
Step-by-step explanation:
It is B because the graph's y-intercept lies on the point (0, -50), hence the equation, y = x <u>- 50</u>. In addition, you can verify that B is the correct answer because the slope of the graph is positive, and so the x-value also must be positive.
<span>Use the definition of continuity.
A function is continuous at a point x = a iff
lim [x → a] f(x) = f(a)
In other words, a function is continuous at a point if its value is equal to its limit at that point.
So, for f(x) to continuous at x = 4 we must have
lim f(x) = f(4)
x → 4
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