Which two points satisfy y=-x2(^)+2x+4 and x+y=4?

1 answer:

5 0

Use subtitution method to solve the problem.

First, change y to the value of x in order to find the exact value of x.
x + y = 4
y = 4 - x

Second, subtitute y with 4 - x from the first equation
y = -x² + 2x + 4
4 - x = -x² + 2x + 4
move all terms to the left side
x² - 2x - x + 4 - 4 = 0
x² - 3x = 0
x(x - 3) = 0
x = 0 or x = 3

Third, now we have 2 values of x. Find the value of y for each of x
For x = 0
y = 4 - x
y = 4 - 0
y = 4

For x = 3
y = 4 - x
y = 4 - 3
y = 1

The solution is (0,4) and (3,1). The answer is option b

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15(1 + 3)

Step-by-step explanation:

15 written in its prime factors is 3 × 5 (15 × 1)

45 written in its prime factors 3 × 3 × 5 (15 × 3)

The greatest common factor is 15: 15 × 1 = 15 and 15 × 3 is 45

∴ 15 + 45 = 15(1 + 3)

Hope this helps! Make me brainiest, lol it's fine if you don't. : )