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eduard
3 years ago
6

Which is the following statements is NOT true?

Mathematics
2 answers:
Dominik [7]3 years ago
6 0

Answer:

The last one is the answer; The slope of AB is different than the slope of BC.

Step-by-step explanation:

nika2105 [10]3 years ago
5 0

Answer:

the last answer choice, my answer got deleted.

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Nick can read 3 pages in 1 minute. write the ordered pairs for nick reading 0,1,2 and 3 min
Elis [28]
For 0 minutes, it would be 0 minutes (obviously)
for 1 minute, it would be 3
for 2 minutes, it would be 6 pages
and finally, 3 minutes, will be 9.
to get the answers, you would just have to add 3, since every minute, nick reads 3 pages.
4 0
3 years ago
$1500 at 9% for 2 years
kotykmax [81]

Answer:$270

Step-by-step explanation:

I=PRT

Interest=principal times rate times time

Principal=1500

Rate=9%=0.09

Time=2

I=1500 times 0.09 times 2

I=1500 times 0.18

I=270

Interest=270

Total is 1500+270=1770 total paid

8 0
3 years ago
Mai has picked 1 cup of strawberries for a cake which is enough for 3/4 of the cake. How many cups does she need for the whole c
Vaselesa [24]

Answer:Mai has picked 1 cup of strawberries for a cake which is enough for 3/4 of the cake. How many cups does she need for the whole cake?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If 2x^2+2x-8 is the quotient when x+3 divides P(x), which of th3 following is the quotient when 2x+6 divides p(x)?
maria [59]

Answer: A

2x^2+2x-8 is the quotient when x+3 divides P(x)

=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)

=> the quotient when 2x+6 divides p(x) is x² + x - 4

Step-by-step explanation:

7 0
2 years ago
Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives
Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

F(x>t)=e^{-\lambda t}

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535

b) The probability of having to wait between 10 and 20 minutes

F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286

5 0
3 years ago
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