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2 years ago

If 12 > -15, which of the following must be true?

Mathematics

1 answer:

Tcecarenko [31]2 years ago

5 0

Answer:

12 is to the right of -15 on a number line.

Step-by-step explanation:

Hope this helps! - CJ

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3x + 7m + 4x - 5m + 25

mart [117]

7x+2m+25 I believe is the answer
So basically I added the x’s first 3x+4x=7x
Next I added the m’s 7m-5m=2m
That left 25
And a + are left
So the two answers 7x+2m and add +25
7x+2m+25

4 0

1 year ago

Let's Apply Solve for the surface area of the following figures. <br><br>please i need this rn

Dafna1 [17]

Answer:

Step-by-step explanation:

1) Surface area of a square = s*s = 12*12 = 144 in

2) Surface area of a Cone = A=πr(r+h2+r2) = 3.142*4(4+22*2+4*2) = 351.904 cm^2

3) S.A of a Cylinder =2πrh+2πr2 = 2*3.142*2*14 + 2*3.142*2*2 = 201.088 m^2

4) S.A of a square Pyramid = a^2 + 2a squareroot (a^2/4 + h^2) = 516.5m^2

5) S.A of a Sphere = 4*pie*r^2 = 4* 3.142*15^2 = 2827.8mm^2

3 0

1 year ago

HELP URGENTLY PLEASE

antiseptic1488 [7]

here's the coordinates

b'= (4,5)

c'= (5,3)

4 0

10 months ago

-6(-4x + 3) = 2(10x + 3)

Naya [18.7K]

Answer:

x = -6/11

Step-by-step explanation:

-6(-4x + 3) = 2(10x + 3)

-6 * -4x = -24x

-6 * 3 = -18

2 * 10x = 20x

2 * 3 = 6

-24x - 18 = 20x + 6

-20x -20x

-44x - 18 = 6

+18 +18

-44x = 24

------- ------

-44 -44

24/-44 = -24/44

-24/44 = -6/22

x = -6/11

8 0

2 years ago

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

2 years ago