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3 years ago

Help with these pls!!

Mathematics

1 answer:

evablogger [386]3 years ago

8 0

#17, x=24
#19, ×=31 are the answers

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PLEASE HELP WITH THIS I GOT 5 MIN LEFT GIVING ALL MY POINTS AND BRAINLIEST PLEASE COME!!!!!!!

yawa3891 [41]

What's the question?

3 0

3 years ago

The graphs of f(x)=2x+4 and g(x)=10−4x intersect at (1, 6) . What is the solution of the equation 2x+4=10−4x ?

Gnoma [55]

Answer:

x=1 is the solution of the equation 2x+4=10−4x

Step-by-step explanation:

The graphs of f(x)=2x+4 and g(x)=10−4x intersect at (1, 6)

2x +4 = 10 - 4x

We need to solve for x by combining like terms

Add 4x on both sides

6x + 4= 10

Now subtract 4 on both sides

6x = 6

divide both sides by 6

x= 1

x=1 is the solution of the equation 2x+4=10−4x

5 0

3 years ago

5) Owen is planting a vegetable

Nana76 [90]

70 I’m pretty sure I’m correct sorry if I’m not:( I’m not to good with math

3 0

3 years ago

Read 2 more answers

Mr. O’Brian is paid $7.30 per hour for 40 hours he works in a week. He is paid 1.5 times that rate for each hour after that

posledela

Hey You!

7.30 × 1.5 = 10.95

10.95 × 40 = 438

So, Mr. O'Brian was paid $438 after he was paid 1.5 times the previous rate for 40 hours.

And That Answers Your Question! :)

3 0

3 years ago

write the equation of the line that passes through the point (-1,-6) and is perpendicular to a line that passes through the poin

Burka [1]

Answer:

$y=\frac{2}{3}x-\frac{16}{3}$

Step-by-step explanation:

step 1

Find the slope of the given line

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

(-2,5) and (-4,8)

substitute the values in the formula

$m=\frac{8-5}{-4+2}$

$m=\frac{3}{-2}$

$m=-\frac{3}{2}$

step 2

Find the slope of the perpendicular line to the given line

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

$m_1=-\frac{3}{2}$ ----> slope of the given line

therefore

$m_2=\frac{2}{3}$ ---> slope of the perpendicular line to the given line

step 2

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{3}$

$point\ (-1,-6)$

substitute

$y+6=\frac{2}{3}(x+1)$

step 3

Convert to slope intercept form

$y=mx+b$

isolate the variable y

$y+6=\frac{2}{3}x+\frac{2}{3}$

$y=\frac{2}{3}x+\frac{2}{3}-6$

$y=\frac{2}{3}x-\frac{16}{3}$

4 0

3 years ago