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nevsk [136]
3 years ago
6

Mariana solved a linear equation and found that it had an infinite number of solutions. Which could have been the final line of

her work?
Mathematics
1 answer:
Fofino [41]3 years ago
4 0

Answer:

0=0

Step-by-step explanation:

Well, the linear equation can be expressed as y=ax+b in the solution of linear equations, there 3 main cases can be concluded as final lines. 1st case - the linear equation has no solution (for example, 0*x=5 has no solutions). 2nd case - the linear equation has one solution (for example 4*x=3 where the only one solution is x=0.75) and the 3rd case - the linear equation has infinite number of solutions (for example 0*x=0). So, in our case (3rd case) the last line can be concluded as 0=0.  

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G) X=4
H) X=2
I) X=-3
J) X=2
8 0
3 years ago
478 cm x 427 cm = ? meters
vekshin1
478×427= 204,106cm
204,106cm - 2041.06m
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5 0
3 years ago
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
3 years ago
Please show your work this question what made you come to the conclusion. Thank you
AveGali [126]

Answer:

B the range, the x- and y-intercept

Step-by-step explanation:

the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.

the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)

3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

8 0
3 years ago
When ms. shreve solved an equation in class, she checked her solution and found that it did not make the equation true! Examine
IgorC [24]
The first part of the second line, she left the -5 there. The correct work and solution should be this:
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<span><span>7x</span>−5</span>=<span><span>5x</span>+<span>9
</span></span>2x-5=9
2x=14
x=7
7 0
3 years ago
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