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Nady [450]
4 years ago
14

Eric jog 3 1/4 mile on Monday, 5 5/8 miles on Tuesday, and 8 miles on Wednesday. Suppose he continues the pattern for the remain

der of the week. How far will Ereck jog on Friday
Mathematics
1 answer:
stepan [7]4 years ago
8 0
<h3>Answer:</h3>

12 3/4 miles

<h3>Step-by-step explanation:</h3>

Eric is increasing his distance by 2 3/8 miles per day. In 2 more days, his distance will be 2×(2 3/8) = 4 3/4 miles more than on Wednesday.

... 8 + 4 3/4 = 12 3/4 . . . . miles on Friday

_____

<em>Rate of increase</em>

The difference between Tuesday and Monday is ...

... 5 5/8 - 3 2/8 = 2 3/8

The difference between Wednesday and Tuesday is ...

... 8 - 5 5/8 = 2 3/8

Thus, it appears that Eric is jogging 2 3/8 mile more each day than the day before.

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Write the slope-intercept form of the equation of each line 13x-2y=14
HACTEHA [7]

Answer:

Step-by-step explanation:

First, lets put this into y=mx+b form.

You can bring the 13x over to the 14, by subtracting and you get -2y=14-13x, or also -2y = -13x + 14

Then you can divide both sides by -2 to get y, and you get

-2y/-2 = -13x/-2 + 14/-2 which is simplified to y=13/2x + (-7) which is

y=13/2x-7

                                {[( IMPORTANT )]}

 THIS HAS THE SLOPE IN A IMPROPER FRACTION... CHECK IF YOU USE MIXED NUMBERS OR IMPROPER FRACTIONS

the mixed number form is y = 7     1/2 x -7

Hope this helps!

       

7 0
3 years ago
A school gymnasium is being remodeled. The basketball court will be similar to an NCAA basketball court, which has a length of 9
valkas [14]

Answer:

Perimeter of NCAA court=288 feet

Perimeter of new court=259.2 feet

Step-by-step explanation:

We are given that

Length of NCAA court, l=94 feet

Width of NCAA court, b=50 feet

Width of new court, b'=45 feet

We have to find the perimeter of an NCAA court and new court in the school.

Perimeter of NCAA court=2(l+b)

Perimeter of NCAA court=2(94+50)feet

Perimeter of NCAA court=288 feet

When two rectangles are similar then  the ration of their   corresponding sides are equal.

Using the  property

\frac{Perimeter\;of\;NCAA\;court}{Perimeter\;of\;new\;court}=\frac{Width\;of\;NCAA\;court}{Width\;of\;new\;court}

\frac{288}{Perimeter\;of\;new\;court}=\frac{50}{45}

Perimeter of new court=\frac{288\times 45}{50} feet

Perimeter of new court=259.2 feet

6 0
3 years ago
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