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3 years ago

(2x+4)^2 - (x-5)^2 = 26x Please solve (explained)

Mathematics

1 answer:

Zina [86]3 years ago

5 0

Expand the squared binomials:

$(2x+4)^2=4x^2+16x+16$

$(x-5)^2=x^2-10x+25$

Then

$(4x^2+16x+16)-(x^2-10x+25)=3x^2+26x-9=26x$

$\implies3x^2-9=0$

$\implies3x^2=9$

$\implies x^2=3$

$\implies x=\pm\sqrt3$

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3 years ago

Read 2 more answers

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

kirill115 [55]

Answer:

The Correct option is Last one $y=-4x-4$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

Step-by-step explanation:

Given:

$y=-4x-3$

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

$y=-4x-3$ ..........Given

Comparing with Slope-Intercept form,

$y=mx+c$

Where m =slope

We get

$Slope = m = -4$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

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3 years ago

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3 years ago

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