Question

(2x+4)^2 - (x-5)^2 = 26x Please solve (explained)

Answer 1

Expand the squared binomials:

$(2x+4)^2=4x^2+16x+16$

$(x-5)^2=x^2-10x+25$

Then

$(4x^2+16x+16)-(x^2-10x+25)=3x^2+26x-9=26x$

$\implies3x^2-9=0$

$\implies3x^2=9$

$\implies x^2=3$

$\implies x=\pm\sqrt3$