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3 years ago

Quadrilateral EFGH is a scaled copy of quadrilateral ABCD. Select all of the true statements.

Mathematics

1 answer:

wariber [46]3 years ago

7 0

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Alexxx [7]

Answer:

Answer is option d

Answer is given below with explanations.

Step-by-step explanation:

We can prove that the two triangles are similar.

We can prove this using AA criterion of similarity.

In triangle DNC and triangle QSC

Vertically opposite angles are equal.

Then Angle QCS = Angle DCN

Two parallel lines cut by a transversal line make the alternate angles are equal.

Then Angle NDC = Angle CQS

By AA criterion of similarity

TRIANGLE DNC ~ TRIANGLE QSC

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

8 0

3 years ago

Read 2 more answers

Adina read 60 out of 100 pages in a comic book.Write the fraction of the pages she read in simplest form

Ad libitum [116K]

Answer:

3/5 is 60/100 in it's simplest form.

Step-by-step explanation:

60 divided by 20 is 3 and 100 divided by 20 is 5.

So 3/5

8 0

2 years ago

What’s 2 plus 2 Pupil:4 That’s good Good?, that’s perfect!

Lesechka [4]

Answer:

Step-by-step explanation:

2+2=4

5 0

2 years ago

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How do I use successive approximations ?

dimaraw [331]

Answer:

assume an approximate value for the variable that will simplify the equation.

solve for the variable.

use the answer as the second approximate value and solve the equation again.

repeat this process until a constant value for the variable is obtained.

7 0

2 years ago

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Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

erik [133]

Answer-

2 is the upper limit for the zeros.

Solution-

The given function f(x) is,

$2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

For calculating the zeros,

$\Rightarrow f(x)=0$

$\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

$\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0$

$\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0$

$\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0$

$\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0$

$\Rightarrow (x-2)(x^2-1)(2x-3)=0$

$\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0$

$\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0$

$\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}$

From all the 4 roots, it can be obtained that 2 is the greatest zero.

7 0

2 years ago