Evaluate when m=20 2 (24)(m)

Nathaniel measured the height of one shelf on his bookcase. He wants to know which books will fit on the shelf. The shelf is 22.

UkoKoshka [18]

PART A - So the ruler is 22.86 centimeters tall, and after measuring with an inch ruler, is also 9 inches tall.
ruler = 22.86cm
ruler = 9 in
You can equate 22.86cm and 9in because they both equal the length of the ruler (transitive property).
22.86cm = 9in
Then you can write a proportionality equation.
$\frac{22.86cm}{9in} = \frac{x}{1in} \\$

Part B -
Cross multiplying,
$(9in)x = (22.86cm)1 \\ 
x = \frac{22.86cm}{9in}= 2.54cm/in$

Part C - We can use something called dimensional analysis - multiplying 12 cm by (1in/2.54cm) - in order to change the units from inches to cm. This is possible because 1in = 2.54cm, the fraction 1in/2.54cm = 1. And also the units cm will cancel out.
$\frac{12cm}{1} * \frac{1in}{2.54cm} = 4.72in$

6 0

3 years ago

I have to show a picture and dont know how

Goshia [24]

Answer:

there should be clip under the text box

Step-by-step explanation:

3 0

3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean 1263 and a stan

DENIUS [597]

Answer:

(a) The 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b) The number of chocolate chips in a bag that make up the middle 95% of bags are [1146, 1380].

(c) The inter-quartile range of the number of chocolate chips in a bag of chocolate chip cookies is 157.83.

Step-by-step explanation:

Let the random variable X represent the number of chocolate chips in a bag of chocolate chip cookies.

The random variable X is normally distributed with mean, μ = 1263 and a standard deviation, σ = 117.

(a)

Compute the 29th percentile for the number of chocolate chips in a bag as follows:

P (X < x) = 0.29

⇒ P (Z < z) = 0.29

The value of z for the above probability is, z = -0.55.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sogma}\\-0.55=\frac{x-1263}{117}\\x=1263-(117\times 0.55)\\x=1198.65$

Thus, the 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b)

According to the Empirical rule 95% of the normally distributed data lies within 2 standard deviations of the mean.

P (μ - σ < X < μ + σ) = 0.95

P (1263 - 117 < X < 1263 + 117) = 0.95

P (1146 < X < 1380) = 0.95

Thus, the number of chocolate chips in a bag that make up the middle 95% of bags are [1146, 1380].

(c)

The inter-quartile range of the normal distribution is:

IQR = 1.349 σ

Compute the inter-quartile range of the number of chocolate chips in a bag of chocolate chip cookies as follows:

IQR = 1.349 σ

= 1.349 × 117

= 157.833

Thus, the inter-quartile range of the number of chocolate chips in a bag of chocolate chip cookies is 157.83.

5 0

3 years ago

Simplify the expression (3.5x - 2.7y) + (-12.8x + 15.8y)

Paladinen [302]

Answer:

−9.3x + 13.1y

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the slope of (3,5) and (-2,1)

fgiga [73]

Answer:

m = 4/5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers