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EastWind [94]
3 years ago
15

Is 4.78778777... a rational or irrational​ number?

Mathematics
1 answer:
Basile [38]3 years ago
8 0

Answer:

irrational is the answer.

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The triangles are similar by the AA Similarity Postulate. Find the value of x.
timofeeve [1]
Hello!

4/5 = (4 + 8)/x
4x = 5(12) = 60
x = 60/4 = 15

I hope this helps!
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3 years ago
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calculate E, the amount of euros that has the same value as D U.S. dollars, using the equation E=17/20D=
Aleksandr [31]

<em>The given equation is:  E=17/20 D  , where  E=amount of Euros and D= amount of U.S dollar. </em>

<em> </em>

<em>Now for 1 U.S dollar, we need to plug D=1 into the above equation. So, we will get......... </em>

<em> E=17/20(1)</em>

<em>E=1/20=0.85</em>

<em>0.85 Euros have the same amount as 1 U.S dollar. </em>

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8 0
3 years ago
NEED ASAP!!!!<br><br> Find the GCF of 72 60 120. show all work!
kari74 [83]
Answer: 12


The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Then the greatest common factor is 12
7 0
3 years ago
Daphne likes to ski at a resort that is open from December through April. According to a sign at the resort, 20, percent of the
Arturiano [62]

Answer:

Step-by-step explanation:

From the given information:

We can compute the  null hypothesis & the alternative hypothesis as:

{H_o}:\text{Distribution of snowfalls in her hometown is similar to claimed percentage }

{H_a}:\text{Distribution of snowfalls in her hometown is not similar to claimed percentage }

The degree of freedom = n - 1

The degree of freedom = 5 - 1

The degree of freedom = 4

At the level of significance of 0.05 and degree of freedom 4,

the rejection region = 9.488

However, we can compute the chi-square X² goodness of fit test as:

   

months  frequency (p)  observed O Expected E  Chi-square X^2= \dfrac{(O-E)^2}{E}

Dec          0.2                  16                   16                \dfrac{(16-16)^2}{16} =0      

Jan           0.250             11                   20                \dfrac{(11-20)^2}{20} =4.050      

Feb           0.200             16                  16                 \dfrac{(16-16)^2}{16} =0      

Mar           0.200             18                  16                 \dfrac{(18-16)^2}{16} =0.250

Apr           0.150               19                  12                 \dfrac{(19-12)^2}{12} =4.083

Total            1.000           80                 80                                  8.3833    

∴

The test statistics X² = 8.3833

Thus; we fail to reject the H_o since test statistics X² doesn't fall in the rejection region.

Therefore; there is sufficient evidence to conclude that the distribution of snowfalls in her hometown is not similar to the claimed percentage.

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3 years ago
Sono Tsume Hoshi Na..
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Answer:

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Step-by-step explanation:

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