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Andrej [43]
3 years ago
5

What is the solution set of -|x| = -8?

Mathematics
1 answer:
n200080 [17]3 years ago
6 0
Your answer is C 8 and -8
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Caryn threw a ball 34.6 m. George threw a ball 34.62 m. Who threw the ball farther?
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George threw the ball farther
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What is an equation of the line that is parallel to y=9−5x and passes through (0, 8) ?
TEA [102]

Answer:

y = -5x Y8  

Step-by-step explanation:

Parallel lines have the same slope.

Your function is

y = 9 − 5x = -5x+ 9

slope = -5

The parallel line

The line must have slope = -5 and include (0, 8), so

8 = -5×(0) + b

8 = 0 + b

b = 8

The equation for the parallel line is

y = -5x + 8

In the diagram below, the red line is the graph of y = 9 -5x.

The parallel blue line is the graph of y = -5x + 8.

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What is the percentage
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The answer to this question is 3976%
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Simplify (5x^-6)^3 leave your answer as a fraction in index form
Elan Coil [88]

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Step-by-step explanation: this should be the answer

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3 years ago
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a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
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