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sergey [27]
3 years ago
11

Find the distance between the points (-4, -2) and (5, 10). If necessary, round your answer to two decimal places.

Mathematics
2 answers:
viktelen [127]3 years ago
6 0
Using the distance formula, the answer would be 15 units
NISA [10]3 years ago
4 0
15, if you plot the points, then seperate the x and y into two seperate lines, you can create a 3,4,5 triangle to find the distance between the points.
You might be interested in
Solve the given integral equation for LaTeX: y(t)y ( t ). LaTeX: y(t)+9\displaystyle{\int_{0}^{t}e^{9(t-v)}y(v)\, dv}=\sin(3t)y
choli [55]

Looks like the equation is

y(t)+9\displaystyle\int_0^te^{9(t-v)}y(v)\,\mathrm dv=\sin(3t)

Differentiating both sides yields the linear ODE,

y'(t)+9e^{9(t-t)}y(t)=3\cos(3t)

or

y'(t)+9y(t)=3\cos(3t)

Multiply both sides by the integrating factor e^{9t}:

e^{9t}y'(t)+9e^{9t}y(t)=3e^{9t}\cos(3t)

\left(e^{9t}y(t)\right)'=3e^{9t}\cos(3t)

Integrate both sides, then solve for y(t):

e^{9t}y(t)=\dfrac1{10}e^{9t}(\sin(3t)+3\cos(3t))+C

y(t)=\dfrac{\sin(3t)+3\cos(3t)}{10}+Ce^{-9t}

The given answer choices all seem to be missing <em>C</em>, so I suspect you left out an initial condition. But we can find one; let t=0, then the integral vanishes and we're left with y(0)=0. So

0=\dfrac{0+3}{10}+C\implies C=-\dfrac3{10}

So the particular solution is

y(t)=\dfrac{\sin(3t)+3\cos(3t)-3e^{-9t}}{10}

6 0
3 years ago
Going to my last resort, brainly
VikaD [51]

Answer:

you have the answer correct actually

Step-by-step explanation:

7 0
2 years ago
What is 2(x+5)&lt;4+5x can i please get answer fast?
Korolek [52]

Answer:

x > 2

Step-by-step explanation:

2(x+5) = 2x + 10 -> 2x + 10 < 4+5x

Subtract 4 from each side.
2x +6 < 5x
Subtract 2x from each side
6 < 3x
2<x

So, x must be > 2

4 0
2 years ago
Please help with two and four
bagirrra123 [75]
Question 1)
575 = 100%
57.5= 10%
57.5 × 2= 115 (20%)

question 2)
575=100%
57.5=10%
115=20%
5.75=1%.

5.75 × 4=22.8 (4%)

22.8 (4%) + 115 (20%) =137.8(24%) which would be rounded up to 138

hope this helps♡♡~~Chyna
4 0
3 years ago
What is the length of missing side JK? Round Answer to nearest tenth please.
zvonat [6]

Given:

Triangle LJK.

LJ = 89 in, LK = 28 in and m∠L = 42°

To find:

The length of missing side JK.

Solution:

LJ = k = 89

LK = j = 28

JK = l = ?

Using law of cosine:

l^{2}=j^{2}+k^{2}-2 jk \cdot \cos L

Substitute the given values.

l^{2}=28^{2}+89^{2}-2 \cdot 28 \cdot 89 \cdot \cos 42^\circ

l^{2}=784+7921-4984 \cdot (0.7)

l^{2}=784+7921-4984 \cdot (0.7431)

l^{2}=784+7921-3703.6

l^{2}=5001.4

Taking square root on both sides.

l=70.7

The length of the missing side is 70.7 in.

4 0
3 years ago
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