Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2
The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67
Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
Answer: Approximately d = 208.72
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Work Shown:
Make sure your calculator is in radian mode
A quick way to check is to compute cos(pi) and you should get -1
cos(angle) = adjacent/hypotenuse
cos(x) = 200/d
cos(0.29) = 200/d
d*cos(0.29) = 200
d = 200/cos(0.29)
d = 208.715135166392 which is approximate
d = 208.72
I rounded to two decimal places since x is rounded in that manner as well. Round however else you need if your teacher instructs.
Just a random guess 22,275 tell me if it right
Answer:
0.375 cups or 3/8
Step-by-step explanation:
divide 3/4, or 0.75 by 2!
