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3 years ago

What is the square root of 112a^2?

Mathematics

1 answer:

marshall27 [118]3 years ago

4 0

That’s ur answer, your welcome

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What is the slope of the line that passes through the points (5, 2) and (3,-1)?

oksano4ka [1.4K]

Slope = -4/5

to calculate the slope m use the gradient form

m = y2 -y1
————
x2 - x1

let (x1, y1) = (3,1) and (x2, y2) = (-2, 5)

m = 5 - 1 4
———- = ——-
-2 - 3 -5

= - 4/5

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1-%28-5%29%7D%7B7-2%7D" id="TexFormula1" title="\frac{1-(-5)}{7-2}" alt="\frac{1-(-5

Eduardwww [97]

Answer:

Step-by-step explanation:

3 0

3 years ago

Please help me answer for 35 and 36

dexar [7]

Answer:

35. $f(2)=16$

36. $f(2)=77$

Step-by-step explanation:

Question 35:

Given:

$f(1)=32$

$f(n)=f(n-1)\times \frac{1}{2}$

Plug in 2 for $n$ and simplify. This gives,

$f(2)=f(2-1)\times \frac{1}{2}\\f(2)=f(1)\times \frac{1}{2}\\f(2)=32\times \frac{1}{2}\\f(2)=16$

Therefore, term 2 is 16.

Question 36:

Given:

$f(1)=11$

$f(n)=f(n-1)\times 7$

Plug in 2 for $n$ and simplify. This gives,

$f(2)=f(2-1)\times 7\\f(2)=f(1)\times 7\\f(2)=11\times 7\\f(2)=77$

Therefore, term 2 is 77.

8 0

3 years ago

15 ÷ 3 = Δ

Vlada [557]

Answer:

A)5 is the answer

Step-by-step explanation:

this is the answer

7 0

3 years ago

Read 2 more answers

The points (-6, r)<br> and<br> (6,3) lie on a line with slope 3/4. Find the missing coordinate r.

NeTakaya

Answer:

r = -6

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Slope 3/4

This means that $m = \frac{3}{4}$ , and thus:

$y = \frac{3}{4}x + b$

(6,3)

This means that when $x = 6, y = 3$ . We use this to find b. So

$y = \frac{3}{4}x + b$

$3 = \frac{3}{4}(6) + b$

$b = 3 - \frac{18}{4} = \frac{12}{4} - \frac{18}{4} = -\frac{6}{4}$

$y = \frac{3}{4}x - \frac{6}{4} = \frac{3x - 6}{4}$

(-6, r)

r is y when $x = -6$ . So

$y = \frac{3(-6) - 6}{4} = -6$

So r = -6.

5 0

3 years ago