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ANEK [815]
3 years ago
8

What is the square root of 112a^2?

Mathematics
1 answer:
marshall27 [118]3 years ago
4 0
That’s ur answer, your welcome

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What is the slope of the line that passes through the points (5, 2) and (3,-1)?
oksano4ka [1.4K]
Slope = -4/5

to calculate the slope m use the gradient form

m = y2 -y1
————
x2 - x1


let (x1, y1) = (3,1) and (x2, y2) = (-2, 5)


m = 5 - 1 4
———- = ——-
-2 - 3 -5


= - 4/5
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1-%28-5%29%7D%7B7-2%7D" id="TexFormula1" title="\frac{1-(-5)}{7-2}" alt="\frac{1-(-5
Eduardwww [97]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
Please help me answer for 35 and 36
dexar [7]

Answer:

35. f(2)=16

36. f(2)=77

Step-by-step explanation:

Question 35:

Given:

f(1)=32

f(n)=f(n-1)\times \frac{1}{2}

Plug in 2 for n and simplify. This gives,

f(2)=f(2-1)\times \frac{1}{2}\\f(2)=f(1)\times \frac{1}{2}\\f(2)=32\times \frac{1}{2}\\f(2)=16

Therefore, term 2 is 16.

Question 36:

Given:

f(1)=11

f(n)=f(n-1)\times 7

Plug in 2 for n and simplify. This gives,

f(2)=f(2-1)\times 7\\f(2)=f(1)\times 7\\f(2)=11\times 7\\f(2)=77

Therefore, term 2 is 77.

8 0
3 years ago
15 ÷ 3 = Δ
Vlada [557]

Answer:

A)5 is the answer

Step-by-step explanation:

this is the answer

7 0
3 years ago
Read 2 more answers
The points (-6, r)<br> and<br> (6,3) lie on a line with slope 3/4. Find the missing coordinate r.
NeTakaya

Answer:

r = -6

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

Slope 3/4

This means that m = \frac{3}{4}, and thus:

y = \frac{3}{4}x + b

(6,3)

This means that when x = 6, y = 3. We use this to find b. So

y = \frac{3}{4}x + b

3 = \frac{3}{4}(6) + b

b = 3 - \frac{18}{4} = \frac{12}{4} - \frac{18}{4} = -\frac{6}{4}

So

y = \frac{3}{4}x - \frac{6}{4} = \frac{3x - 6}{4}

(-6, r)

r is y when x = -6. So

y = \frac{3(-6) - 6}{4} = -6

So r = -6.

5 0
3 years ago
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