Question

What is the general form of the equation of the line shown?

Answer 1

Answer:

$2x-y-3=0$

Step-by-step explanation:

We have been given a graph. We are asked to find the general form of equation of the given line.

We know that general form of equation is in format $ax+by+c=0$.

First of all, we will write equation of our given line in slope intercept form $y=mx+b$.

$m=\frac{3--3}{3-0}$

$m=\frac{3+3}{3}$

$m=\frac{6}{3}$

$m=2$

We can see that y-intercept is $-3$, so our equation in slope-intercept would be: $y=2x-3$.

$y-2x=2x-2x-3$

$y-2x=-3$

$y-2x+3=-3+3$

$-2x+y+3=0$

$-1(-2x+y+3=0)$

$-1*-2x-1*y-1*3=0$

$2x-y-3=0$

Therefore, our required equation is $2x-y-3=0$

Answer 2

The answer is A, because the Y-intersect starts at -2