<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>
The parallelogram in the figure has an area of 
, according to the following formula, which works for all rectangles and parallelograms:
(1)
Where 
is the base and 
is the height
The<u> area of a triangle</u> is given by the following formula:
(2)
So, for option A:
Now, the <u>area of a trapezoid </u>is:
(3)
For option B:
For option C:
>>>>This is the correct option!
For option D:
<h2>Therefore the correct option is C</h2>
Answer:
the answer is 6
Step-by-step explanation:
just divide 150 by 25
All depends on what help you need
X = approximately 633
Steps:
lnx + ln3x = 14
ln3x^2 = 14 : Use the log property of addition which is to multiply same log together so you multiply x and 3x because they have log in common
(ln3x^2) = (14) : take base of e on both sides to get rid of the log
e e
3x^2 = e^14 : e cancels out log on the left side and the right side is e^14
x^2 = e^14 / 3 : divide both sides by 3
√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2 on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself
x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>
x = </span>633.141449221 : solve
Usually, we use the number line to solve inequalities with the symbols,
<
,
≤
,
>
, and
≥
.(the second and last one was rather hard to find on my keyboard) In order to solve an inequality using the number line, though, just turn
the inequality sign to an equal sign. Then, solve the equation. Next step,
graph the point on the number line (remember to graph as an open circle if the
original inequality was <, or >). The number line should now be
divided into 2 regions, one to the left of the graphed point, and one to the
right of said point.
After that, pick a point in both regions and "test" it, check to see if it satisfies
the inequality when plugged in for the variable. If it does, draw a darker line from the point into that region, with an
arrow at the end. That is the solution to the equation: if one
point in the region satisfies the inequality, the entire region will
satisfy the inequality.
I had to check back in an old textbook to remember all of that. Sorry about the earlier answer. That was rather foolish to do so without actually understanding the question.
