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motikmotik
3 years ago
8

Paul has grades of 63 and 81 on his first two tests. What must he score on his third test in order to have an average of at leas

t 70
Mathematics
2 answers:
Yanka [14]3 years ago
5 0
(60+81+s)/3≥70  multiply both sides by 3

60+81+s≥210  combine like terms on left side

141+s≥210  subtract 141 from both sides

s≥69

So Paul will have to score 69 or more on his next test in order to have an average of at least 70.

IgorC [24]3 years ago
3 0
To get an average of at least a 70, Paul would have to get at least a 66 on his third test.
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Please help me I put 100 points for anyone who helps me
LenaWriter [7]

Answer:

a)

<u>The discount id 40%, so the function is:</u>

  • d = 0.4p

b)

  • p = 100 ⇒ d = 40
  • p = 200 ⇒ d = 80
  • p = 300 ⇒ d = 120
  • p = 400 ⇒ d = 160
  • p = 500 ⇒ d = 200

<em>The graph is attached</em>

c)

  • p = $85 ⇒ d = 0.4*$85 = $34

<u>Sale price is:</u>

  • CP = p - d = $85 - $34 = $51

7 0
3 years ago
Read 2 more answers
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
A conversion factor can be written _________ different ways. How do you select the most appropriate conversion factor?
DochEvi [55]

Answer:

can be written two ways

Step-by-step explanation:

A conversion factor is written based on the equality between the two units

5 0
3 years ago
Read 2 more answers
The angles in a pentagon are in a ratio of 7:6:5:5:4. find the measure of the smallest angle
kondaur [170]
This is so hard im so sry i dont get it
6 0
4 years ago
Through (-1,4) and a perpendicular to 4y-2x=12
mart [117]

Answer:

<h2>y = -2x + 2 → 2x + y = 2</h2>

Step-by-step explanation:

\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\\text{then}\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2

\text{We have the equation of a line in the standard form:}\ Ax+By=C.\\\\\text{Convert to the slope-intercept form:}\\\\4y-2x=12\qquad\text{add}\ 2x\ \text{to the both sides}\\\\4y-2x+2x=2x+12\\\\4y=2x+12\qquad\text{divide both sides by 4}\\\\\dfrac{4y}{4}=\dfrac{2x}{4}+\dfrac{12}{4}\\\\y=\dfrac{1}{2}x+3\to\boxed{m_1=\dfrac{1}{2}}

\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2.\\\\\text{Put the value of the slope and the coordinates of the given point (-1, 4)}\\\text{to the equation of a line:}\\\\4=-2(-1)+b\\\\4=2+b\qquad\text{subtract 2 from the both sides}\\\\4-2=2-2+b\\\\2=b\to b=2\\\\\bold{FINALLY:}\ y=-2x+2

\text{Convert to the standard form:}\\\\y=-2x+2\qquad\text{add}\ 2x\ \text{to the both sides}\\\\y+2x=-2x+2x+2\\\\2x+y=2

4 0
4 years ago
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