Answer:
Option A True
Step-by-step explanation:
we know that
The sum of the internal angles of the triangle is equal to 
<u>In the triangle JKL</u>
m∠L=
so
The measurements of the angles of triangle JKL are 
<u>In the triangle WXY</u>
m∠W=
so
The measurements of the angles of triangle WXY are
therefore
Triangle JKL and triangle WXY are similar by AAA ( The AAA postulate states that if you can prove that all three angles of two triangles are congruent, you can prove the two triangles are similar)
First step is to factor. With a polynomial function in the form ax² + bx + c = f(x), we have to find what factors of term C have a sum of term B.
So with this, we need factors of -90 add up to become -1. Your factors are - 10 and 9.
f(x) = x² + 9x - 10x - 90
Now we group together and pull out GCFs.
f(x) = (x² + 9x) + (10x - 90)
f(x) = x(x² + 9) - 10(x + 9)
f(x) = (x - 10)(x + 9)
Now, set each factor equal to zero.
x - 10 = 0, x + 9 = 0
For the first equation you are going to add 10 to both sides to get x by itself. Subtract 9 from both sides in the second equation for the same reason.
x = 10, x = -9
Your zeros are at x = -9, 10 or at the ordered pairs (-9, 0) and (10, 0).
Answer: look at the point
Step-by-step explanation:
Answer:
-36
Step-by-step explanation:
Note that
sin(30°) = 1/2
cos(30°) = √3/2
tan(30°) = 1/√3
cos(45°) = 1/√2
tan(45°) = 1
Therefore
5 sin²(30°) + cos²(45°) - 4 tan²(30°)
= 5*(1/4) + 1/2 - 4*(1/3)
= 5/12
= 0.4167
2 sin(30°) cos(30°) + tan(45°)
= 2(1/2)(√3/2) + 1
= 1.866
Answer: 0.223
