Answer: the number of variations in sign = 3
Step-by-step explanation:
Let the finite sequence 1, –3, 2, 5, –4, –6 , the only pairs of consecutive terms for which the product of the two consecutive terms is negative are :
{1, –3} ; {–3, 2}; {5, –4} then
the number of variations in sign = 3
1/2a - 7 + 1/2a = 1/3
1/2a + 1/2a = 1/3 + 7
2/2a = (1 + 21)/3
a = 22/3
C. point because
it is a definition not a term
Answer:
36
Step-by-step explanation: