AVERAGE between 90 and 100%
means not including 90 and 100% but not including 90 or 100%
average=(sum of values in set)/(how many values in the set)
so
4 exams, so there are 4 values
average=(sum)/4
the sum is the known+unknwon
sum=76+99+86+x
so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100
lets say average=a
a=sum/number
a=(76+99+86+x)/4
90<(76+99+86+x)/4<100
90<(76+99+86+x)/4 and (76+99+86+x)/4<100
solve each for x and find intersection
90<span><</span>(76+99+86+x)/4
times 4 both sides
360<span><</span>261+x
minus 261 both sides
99<span><</span>x
(76+99+86+x)/4<u><</u>100
times 4 both sides
261+x<u><</u>400
minus 261 both sides
x<u><</u>139
so
99<u><</u>x<u><</u>139
since max score is 100
99<u><</u>x<u><</u>100
interval notaion is
[99,100]
answer is 2nd one
Answer:
-23
Step-by-step explanation:
Answer:
x = 4/7
Step-by-step explanation:
x^3 = 64/ 343 // - 64/ 343
x^3 - ( 64/ 343 ) = 0
x^3 - 64 / 343 = 0
1*x^3 = 64/ 343 // : 1
x^3 = 64/ 343
x^3 = 64/ 343 // ^ 1/3
x = 4/ 7
Answer: 9
Step-by-step explanation:
Answer:
false
Step-by-step explanation: