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zysi [14]
3 years ago
12

If you don't know this then im really concerned about your so called "childhood"

SAT
2 answers:
Agata [3.3K]3 years ago
6 0

Answer:

omg i remember singing this noglista :))

Explanation:

antoniya [11.8K]3 years ago
5 0
Yasss, I remember every single kid in my class singing that song repeatedly in
elementary school.
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The area of a rectangle whose width is 5 less than its length.
PSYCHO15rus [73]

Answer:

Explanation:

We know the area of the rectangle is length *  width

We also know width = length - 5

Thus area is length * (length - 5) = (length)^{2}  - 5* length

5 0
2 years ago
What does data warehousing allow organizations to achieve brainly.
Snezhnost [94]

Through data warehousing historical data that can be easily retrieved and analyzed to help improve the organization's operations.

Data warehousing is an electronic representation of information. It refers to organizing, analyzing, and reporting information electronically.

Organizations use data warehousing to store their information electronically so that historical data that can be easily retrieved and analyzed to help improve the organization's operations.

Find out more at: brainly.com/question/8897139

5 0
3 years ago
Pqrs is a parallelogram and st=tr. what is the ratio of the area of a triangle qst to the area of the parallelogram
uranmaximum [27]
1:2 is the answer in all parallelograms!
8 0
3 years ago
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Help please if anyone know that
Paha777 [63]
Where’s the question?
7 0
3 years ago
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Calculate the mass of hydrogen in 57. 010 grams of ammonium hydrogen phosphate.
erastovalidia [21]

The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g  

<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>

1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g

<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>

Mass of H = 6H = 6 × 1 = 6 g

<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>

115 g of (NH₄)H₂PO₄ contains 6 g of H.

Therefore,

57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H

Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄

Learn more about mass composition:

brainly.com/question/13531044

4 0
3 years ago
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